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3 years ago

6

As shown in the figure, a given force is applied to a rod in several different ways. In which case is the torque about the pivot

P due to this force the smallest?

1 answer:

LekaFEV [45]3 years ago

3 0

Answer:

OPTION 5

Explanation:

As the force has no moment arm, it creates no torque about point P.

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A boy on a bicycle is resting at the top of a hill. Then, he rides his bicycle

Andreas93 [3]

Answer:

Top: PE = max, KE = 0

Middle: PE = half, KE = half

Bottom: PE = 0, KE = max

Explanation:

The potential energy of an object is the energy possessed by the object due to its location; it is given by

$PE=mgh$

where

m is the mass of the object

g is the acceleration due to gravity

h is the height of the object from the ground

The kinetic energy of an object is the energy possessed by the object due to its motion; it is given by

$KE=\frac{1}{2}mv^2$

where

v is the speed of the object

Now we analyze the three situations for the boy on the bycicle:

Top of the hill: here h (the height) is maximum, so the potential energy is maximum, while the speed is zero, therefore the kinetic energy is zero.

Middle of the hill: here h (the height) is half of the initial value, therefore the potential energy is also half of the initial potential energy. According to the law of conservation of energy, the total mechanical energy (potential+kinetic) is constant: this means that also the kinetic energy is half of the initial potential energy.

Bottom of the hill: here h is zero, therefore the potential energy is now zero. As a result, all the mechanical energy has been converted into kinetic energy, therefore the kinetic energy is maximum and it is equal to the potential energy of the boy when he was at the top.

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3 years ago

A packing crate slides down an inclined ramp at constant velocity. Thus we can deduce thatA) a frictional force is acting on itb

torisob [31]

Answer:

A) a frictional force is acting on it

Explanation:

The crate is sliding down the inclined ramp at constant velocity: constant velocity means zero acceleration, a = 0. According to Newton's second law:

F = ma

this also means that the net force acting along the direction of the slope is zero.

Without frictional force, there would be only one force acting along this direction: the component of the weight of the crane parallel to the slope, acting downward:

$W_p = mg sin \theta$

where $\theta$ is the angle of the incline. Therefore, the net force along this direction would not be zero. In order to have a net force of zero, there must be another force acting upward on the crate: and the only force that is possibly acting on the crate against its direction of motion is the frictional force, whose magnitude must be equal to $W_p$ , in order to produce a net force of zero (and therefore, a zero acceleration).

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