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2 years ago

8

Shows a few energy levels of the mercury atom. one valence electron is always in the 6s state; the other electron changes states

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1 answer:

Sever21 [200]2 years ago

5 0

Give me some answer choices and i will be happy to help

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What is true about resistance? Check all that apply. A. It is the excess accumulation of electric charge B. It is measured in oh

Alekssandra [29.7K]

Answer:

B, C and E

Explanation:

The unit of resistance in the international system is the Ohm, the equation that describes the resistance is:

$R=p\frac{l}{S} \\$

Where (l) is for lenght of the wire, (S) is the area and (p) its the constant associated to the conductor.

It's related by the Ohm's Law:

$R=\frac{V}{I}$

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2 years ago

In a elastic lab what did you change and why?

Vilka [71]

I changed my undershorts. The elastic on the old ones I put on that day was deteriorated, and it completely failed when I dripped lab coffee on it, causing falldown.

7 0

2 years ago

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An old light bulb draws only 54.3 W, rather than its original 60.0 W, due to evaporative thinning of its filament. By what facto

Lemur [1.5K]

Answer:

The factor of the diameter is 0.95.

Explanation:

Given that,

Power of old light bulb = 54.3 W

Power = 60 W

We know that,

The resistance is inversely proportional to the diameter.

$R\propto\dfrac{1}{D}$

The power is inversely proportional to the resistance.

$P\propto\dfrac{1}{R}$

$P\propto D^2$

We need to calculate the factor of the diameter of the filament reduced

Using relation of power and diameter

$\dfrac{P_{i}}{P_{f}}=\dfrac{D_{i}^2}{D_{f}^2}$

Put the value into the formula

$\dfrac{D_{i}^2}{D_{f}^2}=\dfrac{54.3}{60}$

$\dfrac{D_{i}}{D_{f}}=0.95$

$D_{i}=0.95 D_{f}$

Hence, The factor of the diameter is 0.95.

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2 years ago

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What can Lisa do to increase the strength of the electromagnet?

drek231 [11]

Answer:

move the wire loops closer

Explanation:

because the closer t they are the more concentrated the energy is in that specific area

4 0

2 years ago

The intensity I of light varies inversely as the square of the distance D from the source. If the intensity of illumination on a

emmasim [6.3K]

The intensity on a screen 20 ft from the light will be 0.125-foot candles.

<h3>What is the distance?</h3>

Distance is a numerical representation of the length between two objects or locations.

The intensity I of light varies inversely as the square of the distance D from the source;

I∝(1/D²)

The ratio of the intensity of the two cases;

$\rm \frac{I_1}{I_2} =(\frac{D_2}{D_1} )^2\\\\ \rm \frac{2}{I_2} =(\frac{20}{5} )^2\\\\ \frac{2}{I_2} =4^2 \\\\ I_2= \frac{2}{16} \\\\ I_2= 0.125 \ foot-candles$

Hence, the intensity on a screen 20 ft from the light will be 0.125 foot-candles

To learn more about the distance refer to the link;

brainly.com/question/26711747

#SPJ1

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1 year ago