1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olchik [2.2K]
3 years ago
13

A 5.0-kg block of wood is placed on a 2.0-kg aluminum frying pan. How much heat is required to raise the temperature of both the

wood and the pan from 20°C to 45°C? (Note: The specific heat wood is 1700 J/kg ·°C and of aluminum is 900 J/kg ·°C.)
Physics
1 answer:
Shalnov [3]3 years ago
4 0

Heat required to raise the temperature of a given system is

Q = ms\Delta T

here we know that

m = mass

s = specific heat capacity

\Delta T = change in temperature

now as we know that

mass of wood = 5 kg

mass of aluminium pan = 2 kg

change in temperature = 45 - 20 = 25 degree C

specific heat capacity of wood = 1700 J/kg C

specific heat capacity of aluminium = 900 J/kg C

now here we will find the total heat to raise the temperature of both

Q = m_1s_1\Delta T_1 + m_2s_2\Delta T_2

Q = 5 * 1700 * 25 + 2 * 900 * 25

Q = 212500 + 45000

Q = 257500 J

So heat required to raise the temperature of the system is 257500 J

You might be interested in
What information is given by the formula of an ionic compound?
Sergio [31]
MgCl2 is ionic compound.........Mg +2 and Cl -1
both charges are cross multiplied to each element......formula tells us that to balance the positive and negative charges on both sides they are cross multiplied........MgCl2......meaning there is one atom of Mg and 2 atoms of Cl.......

HOPE IT HELPS !!!
4 0
3 years ago
A simple pendulum consists of a point mass suspended by a weightless, rigid wire in a uniform gravitation field. Check all that
9966 [12]

Answer:

f.The period is independent of the suspended mass.

Explanation:

The period of a pendulum is given by

T=2 \pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration due to gravity

From the formula, we see that:

1) the period of the pendulum depends only on its length, L, and it is proportional to the square root of the length

2) the period does not depend neither on the mass of the pendulum, nor on its amplitude of oscillation

So, the only correct statements are

f.The period is independent of the suspended mass.

Note: statement "e.The period is proportional to the length of the wire" is also wrong, because the period is NOT proportional to the length of the wire, but it is proportional to the square root of it.

3 0
3 years ago
Kwanzaa farts apple juice
8_murik_8 [283]

Answer:

well

Explanation:

7 0
3 years ago
A projectile is fired into the air from the top of a 200-m cliff above a valley as shown below. Its initial velocity is 60 m/s a
anastassius [24]

a) y(max)  = 337.76 m

b) t₁ = 5.30 s  the time for y maximum

c)t₂ =  13.60 s  time for y = 0 time when the fly finish

d) vₓ = 30 m/s        vy = - 81.32 m/s

e)x = 408 m

Equations for projectile motion:

v₀ₓ = v₀ * cosα          v₀ₓ = 60*(1/2)     v₀ₓ = 30 m/s   ( constant )

v₀y = v₀ * sinα           v₀y = 60*(√3/2)     v₀y = 30*√3  m/s

a) Maximum height:

The following equation describes the motion in y coordinates

y  =  y₀ + v₀y*t - (1/2)*g*t²      (1)

To find h(max), we need to calculate t₁ ( time for h maximum)

we take derivative on both sides of the equation

dy/dt  = v₀y  - g*t

dy/dt  = 0           v₀y  - g*t₁  = 0    t₁ = v₀y/g

v₀y = 60*sin60°  = 60*√3/2  = 30*√3

g = 9.8 m/s²

t₁ = 5.30 s  the time for y maximum

And y maximum is obtained from the substitution of t₁  in equation (1)

y (max) = 200 + 30*√3 * (5.30)  - (1/2)*9.8*(5.3)²

y (max) = 200 + 275.40 - 137.64

y(max)  = 337.76 m

Total time of flying (t₂)  is when coordinate y = 0

y = 0 = y₀  + v₀y*t₂ - (1/2)* g*t₂²

0 = 200 + 30*√3*t₂  - 4.9*t₂²            4.9 t₂² - 51.96*t₂ - 200 = 0

The above equation is a second-degree equation, solving for  t₂

t =  [51.96 ±√ (51.96)² + 4*4.9*200]/9.8

t =  [51.96 ±√2700 + 3920]/9.8

t =  [51.96 ± 81.36]/9.8

t = 51.96 - 81.36)/9.8         we dismiss this solution ( negative time)

t₂ =  13.60 s  time for y = 0 time when the fly finish

The components of the velocity just before striking the ground are:

vₓ = v₀ *cos60°       vₓ = 30 m/s  as we said before v₀ₓ is constant

vy = v₀y - g *t        vy = 30*√3  - 9.8 * (13.60)

vy = 51.96 - 133.28         vy = - 81.32 m/s

The sign minus means that vy  change direction

Finally the horizontal distance is:

x = vₓ * t

x = 30 * 13.60  m

x = 408 m

5 0
3 years ago
The three branches of science earth and physicals
seropon [69]
<span>Science is always defined as the body of knowledge and linked to something related to the physical world, phenomena and lives of everything that exist on Earth. Science is categorized in various ways.  Pure, practical or theoretical, is the largest distinction of  science or whether science is applied.  Generally, pure science is subdivided into Physical sciences, Earth sciences, and Life sciences.  Physical sciences deal with energy and matter, Earth sciences explain Earth’s phenomena, to the solar system where it belongs and its atmosphere. And finally, life sciences describe internal processes of living organisms, its relationship to each other and to its environment.</span>


6 0
3 years ago
Other questions:
  • A cleaver physics professor wants to create a situation where a block starts from rest at the top of a 31.0° inclined plane and
    13·1 answer
  • A 3.00 cm diameter coin rolls up a 30.0 degree incline plane. The coin starts with an initial angular speed of 60.0 rad/s in a s
    14·1 answer
  • Why not two magnetic field lines can intersect? why not it is possible?
    13·1 answer
  • Hot air balloons float in the air because of the difference in density between cold and hot air. In this problem, you will estim
    6·1 answer
  • All indicate that the universe is
    15·2 answers
  • 2.486 L is equal to:
    10·2 answers
  • Gravitational Acceleration inside a Planet
    6·1 answer
  • A horizontal force, F1 = 65 N, and a force, F2 = 12.4 N acting at an angle of θ to the horizontal, are applied to a block of mas
    12·1 answer
  • In a heat engine, if 500 J of heat enters the system, and the piston does 300 J of work.
    12·2 answers
  • A woman exerts a horizontal force of 113 N on a crate with a mass of 31.2 kg.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!