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3 years ago

13

If a force of 10 n is applied to an object with a mass of 1kg the object will accelerate at

1 answer:

givi [52]3 years ago

3 0

We Know, F = m*a
Here, F = 10 N
m = 1 Kg

Substitute their values in the equation,
10 = 1 * a
a = 10/1
a = 10

So, your final answer & the acceleration of the object would be 10 m/s²

Hope this helps!

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A small wooden block with mass 0.750 kg is suspended from the lower end of a light cord that is 1.72 m long. The block is initia

Ierofanga [76]

Answer:

$v_{0}=319.2 m/s$

Explanation:

We need to use the momentum and energy conservation.

$p_{0}}=p_{f}$

$mv_{0}=(m+M)V_{1}$

Where:

m is the mass of bullet (m=0.01 kg)
M is the mass of the wooden (M=0.75 kg)
v(0) initial velocity of bullet
V(1) is the velocity of the combined object in the moment the bullet hist the block

Conservation of energy.

We have kinetic energy at first and kinetic and potential energy at the end.

$(1/2)(m+M)V_{1}^{2}=(1/2)(m+M)V_{2}^{2}+(m+M)gh$

Here:

V(1) is the velocity of the combined at the initial position
h is the vertical height ( h = 0.800 m)

We can find V(2) using the definition of force at this point:

$\Sigma F=(m+M)a_{c}=(m+M)(V_{2}^{2}/R)$

$T-(m+M)gcos(\theta)=(m+M)a_{c}=(m+M)(V_{2}^{2}/R)$

$cos(\theta) =(L-h)/L=(1.72-0.8)/1.72$

$\theta =57.66$

Now, we can solve the equation to find V(2)

$V_{2}=\sqrt{\frac{R*(T-(m+M)*g*cos(\theta))}{(m+M)}}$

$V_{2}=\sqrt{\frac{1.72*(4.86-(0.01+0.75)*9.81*cos(57.66))}{(0.01+0.75)}}$

$V_{2}=1.40 m/s$

Now we can find V(1) using the conservation of energy equation

$(1/2)V_{1}^{2}=(1/2)V_{2}^{2}+gh$

$V_{1}=\sqrt{V_{2}^{2}+2gh}$

$V_{1}=\sqrt{1.40^{2}+2*9.81*0.8}$

$V_{1}=4.20 m/s$

Finally, using the momentum equation we find v(0)

$v_{0}=\frac{(m+M)V_{1}}{m}$

$v_{0}=\frac{(0.01+0.75)*4.20}{0.01}$

$v_{0}=319.2 m/s$

I hope it helps you!

7 0

4 years ago

By the nucleus, protons and neutrons of an atom does it contain more mass

Temka [501]

Answer:

Virtually all the mass of an atom resides in its nucleus, according to Chemistry

Explanation:

7 0

3 years ago

andrew-mc [135]

Answer:

S = 2 * pi * 1 m = 6.28 m = distance traveled

V = S / T or T = S / V = 6.28 m / 5 m/s = 1.26 sec

This will be the time for 1 revolution or the period of the motion.

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3 years ago

A dry cell changes ____ energy into ____energy.

zmey [24]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ A dry cell changes chemical energy into electrical energy.

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

5 0

3 years ago

Read 2 more answers

A wire of length 26.0 cm carrying a current of 5.77 mA is to be formed into a circular coil and placed in a uniform magnetic fie

Olin [163]

Answer:

The maximum torque is $\tau_{max} = 1.139 *10^{-7} \ N \cdot m$

Explanation:

From the question we are told that

The length of the wire is $l = 26.0 \ cm = 0.26 \ m$

The current flowing through the wire is $I = 5.77mA = 5.77 *10^{-3} \ A$

The magnetic field is $B = 3.67 \ mT = 3.67 *10^{-3 } T$

The maximum torque is mathematically evaluated as

$\tau_{max} = \mu B$

Where $\mu$ is the magnetic dipole moment which is mathematically represented as

$\mu = \frac{I l^2}{4 \pi n }$

Where $n$ is the number of turns which from the question is 1

substituting values

$\mu = \frac{ 5.77 *10^{-3} * 0.26^2}{4 * 3.142* 1 }$

$\mu = 3.10 4* 10^{-5} A m^2$

Now

$\tau_{max} = 3.104 *10^{-5} * 3.67 *10^{-3}$

$\tau_{max} = 1.139 *10^{-7} \ N \cdot m$

7 0

3 years ago