Answer:
C
Explanation:
If Ami is saying she likes it then it it personal. If you are speaking from statistics and studies it is impersonal and technically not from there perspective. All of these do this except C.
Answer:
Option D is correct: 170 µW/m²
Explanation:
Given that,
Frequency f = 800kHz
Distance d = 2.7km = 2700m
Electric field Eo = 0.36V/m
Intensity of radio signal
The intensity of radial signal is given as
I = c•εo•Eo²/2
Where c is speed of light
c = 3×10^8m/s
εo = 8.85 × 10^-12 C²/Nm²
I = 3×10^8 × 8.85×10^-12 × 0.36²/2
I = 1.72 × 10^-4W/m²
I = 172 × 10^-6 W/m²
I = 172 µW/m²
Then, the intensity of the radio wave at that point is approximately 170 µW/m²
Answer:
λ = 8.716 mm
Explanation:
Given:
- d = 10 cm
- Q >= 5 degrees
Find:
- Find the shortest wavelength of light for which this apparatus is useful
Solution:
- The formula that relates the split difference and angle of separation between successive fringes is given by:
d*sin(Q) = n*λ
Where,
λ: wavelength
d: split separation
Q: angle of separation between successive fringes
m: order number.
- Since this apparatus only shows the first order light so m =1
- the shortest possible wavelength corresponds to:
d*sin(Q) = λ
λ = 0.1*sin(5)
λ = 8.716 mm
Answer:
(a) The value of the ratio m₁/m₂ is 0.581
(b) the acceleration of the combined masses is 1.139 m/s²
Explanation:
Given;
The acceleration of force applied to M₁, a₁ = 3.10 m/s²
The same force applied to M₂ has acceleration, a₂ = 1.80 m/s²
Let this force = F
According Newton's second law of motion;
F = ma
(a) the value of the ratio m₁/m₂
since the applied force is same in both cases, M₁a₁ = M₂a₂
(b) the acceleration of m₁ and m₂ combined as one object under the action force F
F = ma
Therefore, the acceleration of the combined masses is 1.139 m/s²
