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3 years ago

Question 3 of 32

Physics

2 answers:

andrezito [222]3 years ago

5 0

B. located in the atom's nucleus.

Explanation:

Rutherford's experiment using a beam of alpha particles aimed at a sheet of gold foil led him to conclude that an atom's mass is located in the atom's nucleus.

In his experiment, he bombarded a thin gold foil with alpha particles.
He found that most of the alpha particles passed through the foil while a few of them were deflected back.

To explain this, he suggested an atomic model(nuclear model) in which an atom is made up of a small positively charged center or nucleus.

The mass is concentrated in the nucleus.

A large space containing electrons further surrounds the nucleus.

Learn more:

Rutherford brainly.com/question/1859083

#learnwithBrainly

iragen [17]3 years ago

5 0

Answer:the answer is B

Explanation:

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9. A 5.0 kg block on an inclined plane is acted upon by a horizontal force of 100 N shown in the figure below. The coefficient o

Helga [31]

Answer:

A: The acceleration is 7.7 m/s up the inclined plane.

B: It will take the block 0.36 seconds to move 0.5 meters up along the inclined plane

Explanation:

Let us work with variables and set

$m=5kg\\\\F_H=100N\\\\\mu=0.3\\\\\theta=37^o.$

As shown in the attached free body diagram, we choose our coordinates such that the x-axis is parallel to the inclined plane and the y-axis is perpendicular. We do this because it greatly simplifies our calculations.

Part A:

From the free body diagram we see that the total force along the x-axis is:

$F_{tot}=mg*sin(\theta)+F_s-F_Hcos(\theta).$

Now the force of friction is $F_s=\mu*N,$ where $N$ is the normal force and from the diagram it is $F_y=mg*cos(\theta).$

Thus $F_s=\mu*N=\mu*mg*cos(\theta).$

Therefore,

$F_{tot}=mg*sin(\theta)+\mu*mg*cos(\theta)-F_Hcos(\theta)\\\\=mg(sin(\theta)+\mu*cos(\theta))-F_Hcos(\theta).$

Substituting the value for $F_H,m,\mu, and \:\theta$ we get:

$F_{tot}= -38.63N.$

Now acceleration is simply

$a=\frac{F_H}{m} =\frac{-38.63N}{5kg} =-7.7m/s.$

The negative sign indicates that the acceleration is directed up the incline.

Part B:

$d=\frac{1}{2} at^2$

Which can be rearranged to solve for t:

$t=\sqrt{\frac{2d}{a} }$

Substitute the value of $d=0.50m$ and $a=7.7m/s$ and we get:

$t=0.36s.$

which is our answer.

Notice that in using the formula to calculate time we used the positive value of $a$ , because for this formula absolute value is needed.

5 0

3 years ago

The Car That Ran On Chocolate Achieve 3000 - Go On Achieve go to physical science scroll down untill you see The Car That Runs O

worty [1.4K]

Explanation:

Mobil Yang Berlari Di Atas Coklat Mencapai 3000 - Terus Mencapai pergi ke ilmu fisika gulir ke bawah sampai Anda melihat Mobil Yang Berjalan Di Atas Coklat. beri saya semua 8 jawaban dan pertanyaan.

5 0

2 years ago

A pendulum is raised to a height of 0.3m above its lowest point and released. What is the velocity of the pendulum at its lowest

enyata [817]

Answer:

v = 2,425 m / s

Explanation:

A simple pendulum has anergy stored at the highest point of the path and this energy is conserved throughout the movement.

highest point

Em₀ = U = m g y

lowest point

$Em_{f}$ = K = ½ m v²

Em₀ = Em_{f}

mg y = ½ m v²

v = √ 2gy

let's calculate

v = √ (2 9.8 0.3)

v = 2,425 m / s

3 0

3 years ago

The direction of a force can be represented by the length of an arrow.<br> True<br> False

natima [27]

True is The answer would be I just did this

4 0

2 years ago

A 0.50-kg red cart is moving rightward with a speed of 40 cm/s when it collides

lukranit [14]

The momentum of the red cart before the collision is 0.2 kgm/s and the blue cart is 0.

The momentum of the red cart after the collision is 0.05 kgm/s and the blue cart is 0.15 kgm/s.

The change in momentum of the system of the carts is 0.

<h3>Initial momentum of the carts before collision</h3>

The momentum of the carts before the collision is calculated as follows;

P(red) = 0.5 kg x 0.4 m/s = 0.2 kgm/s

P(blue) = 1.5 x 0 = 0

<h3>Momentum of the carts after collision</h3>

The momentum of the carts after the collision is calculated as follows;

P(red) = 0.5 x 0.1 = 0.05 kgm/s

P(blue) = 1.5 0.1 = 0.15 kgm/s

<h3>Change in momentum of the carts</h3>

$\Delta P = P_f - P_i$

ΔP = (0.05 + 0.15) - (0.2)

ΔP = 0

Learn more about momentum here: brainly.com/question/7538238

8 0

1 year ago