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lbvjy [14]
1 year ago
10

The volume of a container is reported as 3.49 ft3. what is the volume in units of in3?

Physics
1 answer:
Kobotan [32]1 year ago
7 0

The volume in units of 6.03x10^3 in3

1ft = 12 inch

So to convert foot into inches we have to multiply by 12

The volume of container = 3.49ft^3

=3.49×12×12×12

= 6030.72 in^3

<h3>What is the volume of a container?</h3>

The amount of space a container encloses, or how much room is inside of it, is measured by its volume. The volume of a box can be calculated using this straightforward formula: volume V = L × W × H for a box with height H, width W, and length L.

Many different units can be used, however because of the way this formula is written, the volume would have length to the third power dimensions. For instance, if the container's measurements are given in metres, the capacity of the box will be given in metres squared, or m3.

To learn more about volume of a container, visit:

brainly.com/question/9092584

#SPJ4

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denpristay [2]

Answer:0.669

Explanation:

Given

mass of clock 93 kg

Initial force required to move it 610 N

After clock sets in motion it requires a force of 514 N to keep moving it with a constant velocity

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\mu _smg=610

\mu _s\times 93\times 9.8=610

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5 0
3 years ago
A man on the moon throws a ball vertically upwards and it is noticed that the ball travels 3.0m less in the fifth second of its
sdas [7]
<h2>Acceleration due to gravity in moon is 1.5 m/s²</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

Here the ball travels 3 m less distance in fifth second compared to third second.

That is

           s₃ = s₅ + 3

Now we have

Distance traveled in third second, s₃ = u x 3 - 0.5 x g x 3² -  u x 2 - 0.5 x g x 2²

           s₃ = u - 2.5 g

Also

Distance traveled in fifth second, s₅ = u x 5 - 0.5 x g x 5² -  u x 4 - 0.5 x g x 4²

           s₅ = u - 4.5 g    

That is

           u - 2.5 g = u - 4.5 g + 3

             2 g = 3

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8 0
2 years ago
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inysia [295]
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5 0
3 years ago
A steel beam that is 5.50 m long weighs 332 N. It rests on two supports, 3.00 m apart, with equal amounts of the beam extending
ElenaW [278]

Explanation:

The given data is as follows.

    Length of beam, (L) = 5.50 m

    Weight of the beam, (W_{b}) = 332 N

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After crossing the left support of the beam by the suki then at some overhang distance the beam starts o tip. And, this is the maximum distance we need to calculate. Therefore, at the left support we will set up the moment and equate it to zero.

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8 0
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balu736 [363]
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3 0
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