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lbvjy [14]
2 years ago
10

The volume of a container is reported as 3.49 ft3. what is the volume in units of in3?

Physics
1 answer:
Kobotan [32]2 years ago
7 0

The volume in units of 6.03x10^3 in3

1ft = 12 inch

So to convert foot into inches we have to multiply by 12

The volume of container = 3.49ft^3

=3.49×12×12×12

= 6030.72 in^3

<h3>What is the volume of a container?</h3>

The amount of space a container encloses, or how much room is inside of it, is measured by its volume. The volume of a box can be calculated using this straightforward formula: volume V = L × W × H for a box with height H, width W, and length L.

Many different units can be used, however because of the way this formula is written, the volume would have length to the third power dimensions. For instance, if the container's measurements are given in metres, the capacity of the box will be given in metres squared, or m3.

To learn more about volume of a container, visit:

brainly.com/question/9092584

#SPJ4

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A sound source A and a reflecting surface B move directly toward each other. Relative to the air, the speed of source A is 28.7
aleksandrvk [35]

(a) 1440.5 Hz

The general formula for the Doppler effect is

f'=(\frac{v+v_r}{v+v_s})f

where

f is the original frequency

f is the apparent frequency

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Here we have

f = 1110 Hz

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In the reflector frame (= on surface B), we have also

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So, the frequency observed in the reflector frame is

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(b) 0.232 m

The wavelength of a wave is given by

\lambda=\frac{v}{f}

where

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In the reflector frame,

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(c) 1481.2 Hz

Again, we can use the same formula

f'=(\frac{v+v_r}{v+v_s})f

In the source frame (= on surface A), we have

v_s = v_B = -62.2 m/s (surface B is now the source, since it reflects the wave, and it is moving towards the receiver)

v_r = +28.7 m/s (surface A is now the receiver, which is moving towards the source)

So, the frequency observed in the source frame is

f'=(\frac{334 m/s+28.7 m/s}{334 m/s-62.2 m/s})1110 Hz=1481.2 Hz

(d) 0.225 m

The wavelength of the wave is given by

\lambda=\frac{v}{f}

where in this case we have

v = 334 m/s

f = 1481.2 Hz is the apparent in the source frame

So the wavelength is

\lambda=\frac{334 m/s}{1481.2 Hz}=0.225 m

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See below

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