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4 years ago

If we know the force, the distance, and the time we can calculate only power. work and power. only work. neither work or power.

2 answers:

7 0

Work = (force) x (distance)

Power = (work) / (time)

Knowing force, distance, and time, it looks like
you can calculate both work and power.

But that's not all !

-- Speed = (distance) / (time)

-- Impulse = change in momentum = (force) x (time)

alexdok [17]4 years ago

4 0

Answer:

Answer is B (work and power) i took the test and got a 100%

Explanation:

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How is most of the electricity we use at home generated?

Sveta_85 [38]

Nuclear power plants, wind farms, water farms, and geothermal heating

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3 years ago

Help me with this plsss

Artist 52 [7]

Answer:

that is going at a constant rate

Explanation:

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3 years ago

A heat pump is used to maintain a house at 22°C by extracting heat from the outside air on a day when the outside air temperatur

Ilia_Sergeevich [38]

Answer:

It is enough

Explanation:

To develop the problem it is necessary to take into account the concepts related to the coefficient of performance of a pump.

The two ways in which the performance coefficient can be expressed are given by:

$COP_p = \frac{T_H}{T_H-T_L}$

Where,

$T_H =$ High Temperature

$T_L =$ Low Temperature

And the other way is,

$COP_p = \frac{\dot{Q}}{W}$

Where $\dot{Q}$ is heat rate and W the power consumed.

We have all our terms in Celsius, so we calculate the temperature in Kelvin

$T_H = 22+273 = 295K$

$T_L = 2+273 = 275k$

The rate at which heat is lost is:

$\dot{Q} = 110000kJ/h$

The power consumed by the heat pump is

$\dot{W} = 5kW$

And the coefficient of performance is

$COP_p = \frac{T_H}{T_H-T_L}$

$COP_p = \frac{295}{295-275}$

$COP_p = 14.75$

With this value we can calculate the Power required,

$COP_p = \frac{\dot{Q}}{W}$

$14.75 = \frac{110000}{W}$

$W = \frac{110000}{3600*14.75}$

$W = 2.07kW$

The power consumed is consumed is 5kW which is more than 2.07kW so this heat pump powerful enough.

4 0

3 years ago

What is fission and how is it related to atomic energy

Amanda [17]

Answer:

Fission is the release of atomic energy related to the splitting of nuclei.

M = M1 + M2 + E where E = m c^2 energy from conversion of mass

if the daughter nuclei are less in total mass than the parent nucleus then the difference is released as atomic energy where E = m c^2 and m is the mass that has been lost in the conversion.

8 0

3 years ago

A car of mass 875 kg is traveling 30.0 m/s when the driver applies the brakes, which lock the wheels. The car skids for 5.60 s i

AleksAgata [21]

Explanation:

It is given that,

Mass of the car, m = 875 kg

Initial speed of the car, u = 30 m/s

Brakes are applied i.e. v = 0

The car skids for 5.60 s in the positive x - direction before coming to rest, t = 5.6

(a) Acceleration of the car, $a=\dfrac{v-u}{t}$