Answer:
<em>The force on each charge = 16 N</em>
Explanation:
From coulombs law,
F = 1/4πε₀(q₁q₂)/d²........................ Equation 1
q₁q₂ = F4πε₀d²...................... Equation 2
Where F = force on the two charges, q₁ = charge on the first body, q₂ = charge on the second body, d = distance of separation, 1/4πε₀ = constant of proportionality.
<em>When d = 1 m, F = 1 N,</em>
<em>Constant: 1/4πε₀ = 9×10⁹ Nm²/C²</em>
<em>Substituting these values into equation 2,</em>
<em>q₁q₂ = 1×1²/9×10⁹ </em>
<em>q₁q₂ = 1/9×10⁹ C²</em>
<em>When d = 1/4 m, q₁q₂ = 1/9×10⁹ C² and 1/4πε₀ = 9×10⁹ Nm²/C²</em>
<em>Substituting these values into equation 1</em>
<em>F = 9×10⁹×1/9×10⁹ /(1/4)²</em>
<em>F = 1/(1/16)</em>
<em>F = 16 N</em>
<em>Therefore the force on each charge = 16 N</em>
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