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tigry1 [53]
3 years ago
13

Which process is used to make low cost energy by nuclear power plant​

Physics
1 answer:
Anika [276]3 years ago
7 0

Fission is used to make the low cost energy

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A proton at location A makes an electricfield E-->1 atlocation B. A different proton, placed atlocation B, experiences a forc
luda_lava [24]

Answer:

Explanation:

 |F-->1| =  E-->1 x charge on proton

= 300 x 1.6 x 10⁻¹⁹

Magnitude of electric force on proton

|F-->1| = 480 x 10⁻¹⁹ N .

Inside lithium nucleus , there are three protons so charge on it

= 3 x 1.6 x 10⁻¹⁹ = 4.8 x 10⁻¹⁹ C .

Magnitude of electric force on lithium nucleus

|F-->Li|  =   E-->1 x charge on lithium nucleus

= 300 x  4.8 x 10⁻¹⁹

= 1440 x 10⁻¹⁹ N .

Electron has same charge as that possessed by proton so charge on electron = 1.6 x 10⁻¹⁹ C

Magnitude of force on electron

|F-->1| =  E-->1 x charge on electron

= 300 x 1.6 x 10⁻¹⁹

=  480 x 10⁻¹⁹ N .

7 0
3 years ago
An artificial satellite is moving in a circular orbit of radius 24,600 km. Calculate its speed if it takes 12hours to revolve ar
denis-greek [22]

Answer:

the speed of the satellite is 12,880.53 km/h

Explanation:

Given;

radius of the circular orbit, r = 24,600 km

time taken to revolve around Earth, t = 12 hours

The circumference of the satellite is calculated as;

L = 2πr

L = 2π x 24,600 km

L = 49,200π km

L = 154,566.36 km

The speed of the satellite;

v = L/t

v = 154,566.36 / 12

v = 12,880.53 km/h

Therefore, the speed of the satellite is 12,880.53 km/h

6 0
2 years ago
As shown in the figure below, a seal and the penguin are playing a fun game of tag. The penguin first swims rightward
RSB [31]

Answer:

Explanation:

Average velocity = Displacement/Time

ΔS = -10+6

ΔS = -4m

Given tme = 30s

Average velocity = -4/30

Average velocity = -0.13m/s

Average speed = Distance/Time

Total distance covered = 10m+6m

Total distance covered = 16m

Average speed = 16/30

Average speed = 0.53m/s

7 0
3 years ago
During which stage of prophase i does crossing over take place?
Rom4ik [11]
Do you mean mitosis? If so metaphase. 
3 0
3 years ago
A screen is separated from a double-slit source by a distance L. When light of wavelength 563 nm is incident on the double slit,
Andrew [12]

Answer:

β 2 = 0.02575 mm

Explanation:

given data

wavelength = 563 nm

separation distance between adjacent bright fringes =  0.0290 mm

wavelength = 500 nm

solution

we get here separation distance between adjacent bright fringes that is express as

β = \frac{\lambda D }{d}    ..................................1

here D is distance from plane of slit to screen

and d is slit sepation that is constant

so

\frac{\beta 1}{\beta 2} = \frac{\lambda 1}{\lambda 2}  

β 2 = \frac{500}{563} \times 0.0290  

β 2 = 0.02575 mm

7 0
3 years ago
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