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liubo4ka [24]
4 years ago
10

What is the electronic structure of V2+?

Chemistry
1 answer:
Tanzania [10]4 years ago
6 0
<h3>Answer:</h3>

V²⁺ =  [Ar] 3d³

<h3>Explanation:</h3>
  • Elements can either lose or gain an electron(s) to attain an octet configuration and form ions.
  • Metals lose an electron(s) to attain a stable configuration and form positively charged ions called cations.
  • Non-metals, on the other hand, gain an electron(s) to attain an octet configuration and form negatively charged ions known as anions.
  • In this case, Vanadium is a transitional element with 5 valence electrons.
  • Like other transition elements, vanadium may have multiple oxidation numbers.
  • Vanadium has an atomic number of 23 and a configuration of [Ar] 3d³4s², therefore, vanadium ion (V²⁺) formed by loss of two electrons will have a configuration of [Ar] 3d³
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