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4 years ago

What is the electronic structure of V2+?

Chemistry

1 answer:

Tanzania [10]4 years ago

6 0

<h3>Answer:</h3>

V²⁺ = [Ar] 3d³

<h3>Explanation:</h3>

Elements can either lose or gain an electron(s) to attain an octet configuration and form ions.
Metals lose an electron(s) to attain a stable configuration and form positively charged ions called cations.
Non-metals, on the other hand, gain an electron(s) to attain an octet configuration and form negatively charged ions known as anions.
In this case, Vanadium is a transitional element with 5 valence electrons.
Like other transition elements, vanadium may have multiple oxidation numbers.
Vanadium has an atomic number of 23 and a configuration of [Ar] 3d³4s², therefore, vanadium ion (V²⁺) formed by loss of two electrons will have a configuration of [Ar] 3d³

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Heat energy can be calculated by using the specific heat of a substance multiplying it to the mass of the sample and the change in temperature. It is expressed as:

<span>Energy = mCΔT</span>

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4 years ago

Read 2 more answers

A buffer with a pH of 4.31 contains 0.31 M of sodium benzoate and 0.24 M of benzoic acid. What is the concentration of [ H 3 O ]

Mnenie [13.5K]

<u>Answer:</u> The hydronium ion concentration in the solution is $1.29\times 10^{-4}M$

<u>Explanation:</u>

To calculate the molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles hydrochloric acid solution = 0.060 mol

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of HCl}=\frac{0.060}{1L}\\\\\text{Molarity of HCl}=0.060M$

The chemical reaction for aniline and HCl follows the equation:

$C_6H_5COO^-+HCl\rightarrow C_6H_5COOH+Cl^-$

<u>Initial:</u> 0.24 0.060 0.31

<u>Final:</u> 0.18 - 0.37

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{conjugate acid}]}{[\text{base}]})$

$pH=pK_a+\log(\frac{[C_6H_5COO^-]}{[C_6H_5COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of benzoic acid = 4.2

$[C_6H_5COO^-]=0.18M$

$[C_6H_5COOH]=0.37M$

pH = ?

Putting values in equation 1, we get:

$pH=4.2+\log(\frac{0.18}{0.37})\\\\pH=3.89$

To calculate the hydronium ion concentration in the solution, we use the equation:

$pH=-\log[H_3O^+]$

pH = 3.89

Putting values in above equation, we get:

$3.89=-\log[H_3O^+]$

$[H_3O^+]=10^{-3.89}=1.29\times 10^{-4}M$

Hence, the hydronium ion concentration in the solution is $1.29\times 10^{-4}M$

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3 years ago

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Aleksandr [31]

Answer: Albedo

Explanation:

((Earth's normal albedo is about 0.3.)))

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4 years ago

1 Point

azamat

Answer:

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Explanation:

In a double-displacement reaction two molecules will exchange atoms or group of atoms, and it should look like this:

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XY + O $_{2}$ → XO + YO

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XY + A → XA + Y

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