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Natali5045456 [20]
3 years ago
5

A 2.0-kilogram laboratory cart is sliding across a horizontal frictionless surface at a constant velocity of 4.0 meters per seco

nd east. What will be the cart's velocity after a 6.0-newton westward force acts on it for 2.0 seconds?
(1) 2.0 m/s east
(2) 10.0 m/s east
(3) 2.0 m/s west
(4) 10.0 m/s west
Physics
1 answer:
yanalaym [24]3 years ago
7 0

Answer:

(2) 10.0 m/s east

Explanation:

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. Maria walked 1.5 miles south to her house in 0.5 hours. What is her speed in miles per hour?
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v=\frac{d}{t}

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v=\frac{1.5}{0.5}=3 mi/h

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F = kqq'/r²........................... Equation 1

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make r the subject of the equation above

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Given: q = q' = 0.005 C, F = 750 N

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Hence the distance between the pair of charges = 17.32 m

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