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adelina 88 [10]
3 years ago
10

Assuming Luke has a mass of 90Kg how much potential energy does he have just as he leaves the plane 7620 meters up? Explain how

you know.
Physics
1 answer:
Bond [772]3 years ago
4 0

Answer : P = 6858 KJ

Explanation :

Mass of Luke, m = 90 Kg

Height, h = 7620 m

Acceleration due to gravity, g = 10\ m/s^2

Gravitational potential energy, P = m\times g\times h

So, P = 90\times 10\times 7620

P = 6858 KJ

Hence, the potential energy is 6858 KJ.

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A 300 kg buffalo runs across the prairie with a speed of 8 m/s. What is the kinetic energy of the Buffalo? A:19,200 j B:9600 j C
alina1380 [7]
<h2>Answer: 9600 J</h2>

The kinetic energy K  of a body is that energy it possesses due to its movement and is defined as:

K=\frac{1}{2}mV^{2}

Where m is the mass of the body and V its velocity .

This has to do with the speed of an object and how much mass it has; basically how the object is moving.

Now, according to this equation and knowing that the mass of the buffalo is m=300kg  and its velocity V=8m/s :

K=\frac{1}{2}(300kg)(8m/s)^{2}

K=9600J

Therefore the correct option is B.

5 0
3 years ago
A cyclist is riding a bicycle at a speed of 22 mph on a horizontal road. The distance between the axles is 42 in., and the mass
stealth61 [152]

Answer:

The shortest distance is  S = 24.86 ft

Explanation:

The free body diagram of this question is shown on the first uploaded image

From the question we are told that

   The speed of the bicycle is v_b = 22\ mph = 22 * \frac{5280}{3600}   =  32.26 ft/s

     The distance between the axial is  d = 42 \ in

The mass center of the cyclist and the bicycle is m_c = 26 \ in  behind the front axle

The mass center of the cyclist and the bicycle is m_h = 40 \ in above the ground

   For the bicycle not to be thrown over the

     Momentum about the back wheel must be zero so

                \sum _B = 0

=>             mg (26) = ma(40)

=>             a = \frac{26}{40} g

Here  g = 32.2 ft/s^2

     So     a =  \frac{26}{40} (32.2)

             a =  20.93 ft/s^2

Apply the equation of motion to this motion we have

       v^2 = u^2 + 2as

 Where  u = 32.26 ft /s

             and v = 0 since the bicycle is coming to a stop

        v^2 = (32.26)^2 - 2(20.93) S

=>      S = 24.86 ft        

                 

5 0
3 years ago
2) A sprig with a length of 15 cm and stores 110 J of potential energy when stretched to a new
Alik [6]

Answer:

94.28 cm

Explanation:

The formula for elastic potential energy is given as;

PEel = 1/2 *k*x² where x is the displacement, k is the spring constant

Given

PEel = 110 J, k= 350 N/m  then find x

PEel = 1/2 *k*x²

110 = 1/2 * 350 * x²

110 = 175 x²

110/175 = x²

0.6286=x²

√0.6286 =x

0.7928 m = x

79.28 cm = x

New length of spring = 15 cm + 79.28 cm = 94.28 cm

4 0
3 years ago
the very high voltage needed to create a spark across the spark plug is produced at the a. transformer's primary winding. b. tra
Karo-lina-s [1.5K]
I think the correct answer from the choices listed above is option B. The very high voltage needed to create a spark across the spark plug is produced at the  transformer's secondary winding. <span>The secondary coil is engulfed by a powerful and changing magnetic field. This field induces a current in the coils -- a very high-voltage current.</span>
5 0
3 years ago
Read 2 more answers
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Kamila [148]

The two basic defenses in basketball are man-to-man, sometimes referred to as person-to-person in respect for the rise of women's basketball, and zone. Each basic defense has a number of variations.

4 0
3 years ago
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