As a result of high winds and water from a storm surge, homes, businesses, and crops may be destroyed or damaged, public infrastructure may also be compromised, and people may suffer injuries or loss of life.
The first step in the two-step process of making a solution is the breakdown of the solute source into Atomic particles
for a solution to break the solute must be dissociated and break into the atomic particles
so correct option is D
hope it helps
Answer:
Amount of excess Carbon (ii) oxide left over = 23.75 g
Explanation:
Equation of the reaction: Fe₂O₃ + 3CO ----> 2Fe + 3CO₂
Molar mass of Fe₂O₃ = 160 g/mol;
Molar mass of Carbon (ii) oxide = 28 g/mol
From the equation of reaction, 1 mole of Fe₂O₃ reacts with 3 moles of carbon (ii) oxide; i.e. 160 g of iron (iii) oxide reacts with 84 g (3 * 28 g) of carbon (ii) oxide
450 g of Fe₂O₃ will react with 450 * 84/180) g of carbon (ii) oxide = 236..25 g of carbon (ii) oxide
Therefore the excess reactant is carbon (ii) oxide.
Amount of excess Carbon (ii) oxide left over = 260 - 236.25
Amount of excess Carbon (ii) oxide left over = 23.75 g
Answer:
The average velocity of the airplane for this trip is 1684.21 km/h
Explanation:
Average velocity is the rate of change of displacement with time. That is,
Average velocity =
= Δx / Δt = ![\frac{x2 - x1}{t2 - t1}](https://tex.z-dn.net/?f=%5Cfrac%7Bx2%20-%20x1%7D%7Bt2%20-%20t1%7D)
Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.
From,
Velocity = ![\frac{Distance traveled}{Time taken}](https://tex.z-dn.net/?f=%5Cfrac%7BDistance%20traveled%7D%7BTime%20taken%7D)
Time = ![\frac{Distance traveled}{Velocity}](https://tex.z-dn.net/?f=%5Cfrac%7BDistance%20traveled%7D%7BVelocity%7D)
Therefore, Time = ![\frac{2100km }{1000km/h}](https://tex.z-dn.net/?f=%5Cfrac%7B2100km%20%7D%7B1000km%2Fh%7D)
Time = 2.1h
This is the time taken before the airplane encounters a wind.
Hence, t1 = 2.1h
Now, For the time taken by the airplane when it encounters a wind
Also from,
Velocity = ![\frac{Distance traveled}{Time taken}](https://tex.z-dn.net/?f=%5Cfrac%7BDistance%20traveled%7D%7BTime%20taken%7D)
Time = ![\frac{Distance traveled}{Velocity}](https://tex.z-dn.net/?f=%5Cfrac%7BDistance%20traveled%7D%7BVelocity%7D)
Therefore, Time = ![\frac{1300km }{800km/h}](https://tex.z-dn.net/?f=%5Cfrac%7B1300km%20%7D%7B800km%2Fh%7D)
Time = 1.625h
Hence, t2 = 1.625h
Now, to calculate the average velocity
Average velocity = ![\frac{x2 - x1}{t2 - t1}](https://tex.z-dn.net/?f=%5Cfrac%7Bx2%20-%20x1%7D%7Bt2%20-%20t1%7D)
x1= 2100, x2= 1300, t1= 2.1h and t2= 1.625h
Hence, Average velocity = ![\frac{1300 - 2100}{1.625 - 2.1}](https://tex.z-dn.net/?f=%5Cfrac%7B1300%20-%202100%7D%7B1.625%20-%202.1%7D)
Average velocity = 1684.21 km/h