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3 years ago

Compare and contrast repetition and replication in a science investigation

1 answer:

3 0

Repetition occurs when multiple sets of measurements are made during one scientific investigation. Replication occurs when a scientific investigation is <span>reproduced by another person.

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Wilma can mow a lawn in 80 minutes. Rocky can mow the same lawn in 120 minutes. Construct an equation that would allow you to de

xeze [42]

Answer:

$t = 96 minutes$

Explanation:

Time to mow 1 lawn by Wilma is 80 minutes

so work done in 1 minute by Wilma is given as

$W_1 = \frac{1}{80}$

Similarly Rocky mow same lawn in 120 minute

so work done in 1 minute by Rocky is given as

$W_2 = \frac{1}{120}$

now we know that they both worked by "t" time

so total work performed by them

$W = \frac{t}{80} + \frac{t}{120}$

they both mow 2 lawns then it is given as

$2 = (\frac{1}{80} + \frac{1}{120})t$

$t = 96 minutes$

5 0

3 years ago

Is it true or not true

maria [59]

Answer:

true

Explanation:

6 0

3 years ago

What is the only function of the pulleys in the diagram?

tia_tia [17]

The only function of the pulleys in the diagram is to change the direction

of the force applied to raise the bricks.

<h3>What is a Pulley?</h3>

A pulley is a wheel which has a flexible rope on its rim and helps to

transmit energy and motion.

In the diagram given, we can see that the pulley is used to raise a mass of

block by three people. They pull the rope horizontally in order to raise the

block vertically. This means that it was used to change the direction of the

applied force.

Read more about Pulley here brainly.com/question/177456

5 0

3 years ago

A charged box ( m = 495 g, q = + 2.50 μ C ) is placed on a frictionless incline plane. Another charged box ( Q = + 75.0 μ C ) is

Rudik [331]

Answer:

$a=16.2m/s^{2}$

Explanation:

From the attached file diagram, the total force acting on the charged box is the downward weight and the repulsive force acting in opposite to the weight force . Hence we can write the total force as

$F=masin\alpha -\frac{kQq}{r^{2}} \\\alpha =35^{0}, m=0.495kg, r=0.61m, Q=2.5*10^{-6}, q=75.0*10^{-6}\\$

When fixed,F=o

Hence

$masin\alpha =\frac{kQq}{r^{2}}\\0.495kg*asin35=\frac{9*10^{9}*2.5*10^{-6}*75.0*10^{-6}}{0.61^{2}} \\0.28a=4.5351\\a=\frac{4.5351}{0.28}\\\\ a=16.2m/s^{2}$

The value of the acceleration is 16.2m/s^2

7 0

3 years ago

What is relative velocity?

joja [24]

Search it up bruhhhhhhhhhhhhh

5 0

3 years ago

Read 2 more answers