Your answer would be an Element can't be separated into simpler substances or converted into another substance by chemical process.

Hope that helps!!!

8 0

3 years ago

Consider the following combustion reaction:

ZanzabumX [31]

Answer:

vxcvggccbbcCbnmhxx vgfscvjjg

6 0

3 years ago

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Determine the expected diffraction angle for the first-order diffraction from the (111) set of planes for FCC nickel (Ni) when m

faust18 [17]

Answer:

56°

Explanation:

First calculate $a:$

$a=2 R \sqrt{2}=2(0.1246) \sqrt{2}=0.352 \mathrm{nm}$

The interplanar spacing can be calculated from:

$d_{111}=\frac{a}{\sqrt{1^{2}+1^{2}+1^{2}}}=\frac{0.352}{\sqrt{3}}=0.203 \mathrm{nm}$

The diffraction angle is determined from:

$\sin \theta=\frac{n \lambda}{2 d_{111}}=\frac{1(0.1927)}{2(0.2035)}=0.476$

Solve for $\theta$

$\theta=\sin ^{-1}(0.476)=28^{\circ}$

The diffraction angle is:

$2 \theta=2\left(28^{\circ}\right)=56^{\circ}$

4 0

3 years ago

A student titrated 20 ml of 0.410 m hcl with 0.320 m naoh. determine the volume of naoh needed at equivalence point

Aleksandr-060686 [28]

Answer:

25.6mL NaOH

Explanation:

We are given the Molarity of the solution ( $\frac{moles}{liters}$ ) and the volume of the solution (.02L).

By multiplying the two together, we can find the moles of solution that are reacted with HCl.

$moles = \frac{.410 moles}{L} *.02L$

This gives us .0082 moles of HCl.

We then find the moles of NaOH that are needed to react with the HCl using the equation.

$HCl + NaOH = NaCl + H_{2} O$

As HCl and NaCl have a 1:1 ratio, we need .0082 mol of NaOH.

Dividing this value by the Molarity of the solution

$\frac{.0082mol}{.320mol/L}$

Gives us the answer, in Liters (.0256), which we can then divide by 100 convert to mL.

3 0

3 years ago