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vodka [1.7K]
3 years ago
15

Which lists the elements in order from least conductive to most conductive?

Chemistry
2 answers:
TEA [102]3 years ago
6 0

Answer:

It's A) nitrogen (N), antimony (Sb), bismuth (Bi)

Explanation: Just got it from the test

AfilCa [17]3 years ago
5 0

nitrogen (N), antimony (Sb), bismuth (BI)

Explanation:

Electrical conductance increases from Nitrogen to antimony and then Bismuth. Electrical conductance increases with available free electrons.

  • The elements listed belongs to Group V on the periodic table.
  • Group V elements are Nitrogen, Phosphorus, Arsenic, Antimony, Bismuth.
  • As we go down the group, electrical conductance increases.
  • This is because the radius of the atom becomes larger and the pull on the outer electrons become very weak.
  • Outer electrons becomes free to facilitate electrical conductance.
  • We can also see that metallicity i.e electropositivity increases down the group.

Learn more:

Metallic bonds brainly.com/question/6071838

#learnwithBrainly

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An atom has 6 electrons in its outer orbit. It will most likely form an ion with a charge of:
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Carlos stomps a soda con flat and throw it away. Which of the following statements BEST describes the change made in the soda ca
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3 years ago
When the following equation is balanced, what is the coefficient for CaCl2 ?
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6 0
3 years ago
100.0 mL of 3.8M NaCN, the minimum lethal concentration of sodium cyanide in blood serum
9966 [12]

The given question is incomplete. The complete question is:

Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

Answer: The number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

3.8\times 10^{-5}M=\frac{n\times 1000}{100.0}

n=0.38\times 10^{-5}

n = moles of NaCN = \frac{\text {given mass}}{\text {Molar mass}}

0.38\times 10^{-5}=\frac{x}{49g/mol}

x=18.62\times 10^{-5}g

Thus the number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

6 0
3 years ago
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