If this decay has a half-life of 10.2 years, what mass of 60.8g carbon-14 will remain after 20.4 years
1 answer:
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Answer:
The shortest de Broglie wavelength for the electrons that are produced as photoelectrons is 0.81 nm
Explanation:
Given;
wavelength of ultraviolet light, λ = 270 nm
work function of the metal, φ = 2.3 eV = 2.3 x 1.602 x 10⁻¹⁹ J = 3.685 x 10⁻¹⁹ J
The energy of the ultraviolet light is given by;
The energy of the incident light is related to kinetic energy of the electron and work function of the metal by the following equation;
E = φ + K.E
K.E = E - φ
K.E = (7.362 x 10⁻¹⁹ J) - (3.685 x 10⁻¹⁹ J )
K.E = 3.677 x 10⁻¹⁹ J
K.E = ¹/₂mv²
mv² = 2K.E
velocity of the electron is given by;
the shortest de Broglie wavelength for the electrons is given by;
Therefore, the shortest de Broglie wavelength for the electrons that are produced as photoelectrons is 0.81 nm
Answer:
0.37 m
Explanation:
The angular frequency, ω, of a loaded spring is related to the period, T, by
The maximum velocity of the oscillation occurs at the equilibrium point and is given by
A is the amplitude or maximum displacement from the equilibrium.
From the the question, T = 0.58 and A = 25 cm = 0.25 m. Taking π as 3.142,
To determine the height we reached, we consider the beginning of the vertical motion as the equilibrium point with velocity, v. Since it is against gravity, acceleration of gravity is negative. At maximum height, the final velocity is 0 m/s. We use the equation
is the final velocity,
is the initial velocity (same as v above), a is acceleration of gravity and h is the height.