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suter [353]
3 years ago
6

An proton moves with a velocity of bold v with bold rightwards harpoon with barb upwards on top equals open parentheses 5.00 spa

ce bold i with bold hat on top minus 6.00 space bold italic j with hat on top plus 1.00 space k with hat on top close parentheses space space straight m divided by straight s in a region in which the magnetic field is bold italic B with bold rightwards harpoon with barb upwards on top equals open parentheses 1.00 space bold i with bold hat on top plus 2.00 space bold italic j with hat on top minus 1.00 space k with hat on top close parentheses space space straight T. The electric charge carried by a proton is 1.60 cross times 10 to the power of negative 19 end exponent space straight C. What is the magnitude of the magnetic force this proton experiences
Physics
1 answer:
exis [7]3 years ago
4 0

Answer:

2.64*10^-18 N

Explanation:

You have the following vectors:

\vec{v}=5.00\hat{i}-6.00\hat{j}+1.00\hat{k}\\\\\vec{B}=1.00\hat{i}+2.00\hat{j}-1.00\hat{k}

The magnitude of the magnetic force is given by the following equation:

|\vec{F_B}|=q|\vec{v}\ X\ \vec{B}|

Thus, you calculate the cross product between v and B (for example with the determinant method) and you obtain:

\vec{v}\ X\ \vec{B}=4\hat{i}-\hat{j}+16\hat{k}

Finally the magnitude of the force will be:

|\vec{F_B}|=(1.6*10^{-19}C)\sqrt{(4)^2+(-1)^2+(16)^2}N=2.64*10^{-18}N

then, the magnetic force is 2.64*10^-18 N

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What is a constellation as astronomers define it today? What does it mean when an astronomer says, “I saw a comet in Orion last
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4 0
3 years ago
Three masses are located in the x-y plane as follows: a mass of 6 kg is located at (0 m, 0 m), a mass of 4 kg is located at (3 m
Natali [406]
<h2>Answer:</h2>

D. (1m, 0.5m)

<h2>Explanation:</h2>

The center of mass (or center of gravity) of a system of particles is the point where the weight acts when the individual particles are replaced by a single particle of equivalent mass. For the three masses, the coordinates of the center of mass C(x, y) is given by;

x = (m₁x₁ + m₂x₂ + m₃x₃) / M       ----------------(i)

y = (m₁y₁ + m₂y₂ + m₃y₃) / M       ----------------(ii)

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m₂ and x₂ = mass and position of second mass in the x direction.

m₃ and x₃ = mass and position of third mass in the x direction.

y₁ , y₂ and y₃ = positions of the first, second and third masses respectively in the y direction.

From the question;

m₁ = 6kg

m₂ = 4kg

m₃ = 2kg

x₁ = 0m

x₂ = 3m

x₃ = 0m

y₁ = 0m

y₂ = 0m

y₃ = 3m

M = m₁ + m₂ + m₃ = 6 + 4 + 2 = 12kg

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x = ((6x0) + (4x3) + (2x0)) / 12

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y = 6 / 12

y = 0.5m

Therefore, the center of mass of the system is at (1m, 0.5m)

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