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Lelechka [254]
3 years ago
12

A particle that orbits the nucleus in an atom is called a(n

Chemistry
2 answers:
Morgarella [4.7K]3 years ago
7 0
Particles that orbit the nucleus are called electrons.

Explanation: Electrons are negatively charged particles arranged in orbits  around the nucleus of an atom and determining all of the atom's physical and chemical properties  except mass and radioactivity.
drek231 [11]3 years ago
5 0
 The particles is called Electrons 
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Answer:

Explanation:

The fertility of soil is improved decomposition.

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3 years ago
A 48.3 mL sample of gas in a cylinder is warmed from 22 °C to
goldenfox [79]

Answer:

58.94 mL

Explanation:

V1 = 48.3 mL             V2 = v mL

T1 = 22 degree celsius OR 295 k         T2 = 87 degree celsius OR 360 k

We will use the gas equation:

PV = nRT

Since the Pressure (p) , number of moles (n) and the universal gas constant(R) are all constants in this given scenario,

we can say that

V / T = k , (where k is a constant)

Since this is the first case,

V1 / T1 = k --------------------(1)

For case 2:

Since we have the same constants, the equation will be the same

V / T = k (where k is the same constant from before)

V2 / T2 = k (Since this is the second case) ------------------(2)

From (1) and (2):

V1 / T1 = V2 / T2

Now, replacing the variables with the given values

48.3 / 295 = v / 360

v = 48.3*360 / 295

v = 58.94 mL

Therefore, the final volume of the gas is 58.94 mL

4 0
3 years ago
How do you balance this?
ad-work [718]
Weigh them both and there you go
8 0
3 years ago
From the data table given, calculate the missing quantity
ololo11 [35]

<u>Answer:</u> The initial volume of the gas is 16.55 mL

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=?mL\\T_1=300K\\V_2=16mL\\T_2=290K

Putting values in above equation, we get:

\frac{V_1}{300K}=\frac{16mL}{290K}\\\\V_1=\frac{16\times 300}{290}=16.55mL

Hence, the initial volume of the gas is 16.55 mL

4 0
4 years ago
In an experiment Teresa's measures 15.5 mL of water she must have used a
kotykmax [81]

Answer:

transfer pipet that had markings every 0.1 mL.

Explanation:

3 0
4 years ago
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