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eduard
3 years ago
13

PLEASE HELP ME

Physics
2 answers:
KATRIN_1 [288]3 years ago
6 0

B.Low levels of fecal coliform

posledela3 years ago
5 0
Low levels of fecal coliform
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When a machine is used to do work, the force applied by the machine is called the effort force?
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3. An automobile accelerates 1.77 m/sover 6.00 s to reach the freeway speed at
Effectus [21]

The initial speed of the automobile is 49.84km/hr

<u>Explanation:</u>

Given:

Acceleration, a = 1.77 m/s²

Time, t = 6s

Final speed, v = 88 km/h

                     v = 88 X 0.278 m/s

                     v = 24.464 m/s

Initial speed, u = ?

We know,

v = u + at

On substituting the value in the formula we get:

24.464 = u + (1.77 X 6)

24.464 = u + 10.62

u = 24.464 - 10.62 m/s

u = 13.844 m/s

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Therefore, the initial speed of the automobile is 49.84km/hr

4 0
4 years ago
Ask Your Teacher Two long, straight wires are parallel and 11 cm apart. One carries a current of 2.9 A, the other a current of 5
dsp73

Answer:

The magnitude of force per unit length of one wire on the other is 2.7945\times 10^{-5}\ N and the direction is away from one another

The magnitude of force per unit length of one wire on the other is 2.7945\times 10^{-5}\ N and the direction is towards each other.

Explanation:

\mu_0 = Vacuum permeability = 4\pi\times 10^{-7}\ N/A^2

i_1 = Current in first wire = 2.9 A

i_2 = Current in second wire = 5.3 A

r = Gap between the wires = 11 cm

Force per unit length

F_{12}=F_{21}=\frac{\mu_0 i_1i_2}{2\pi r}\\ =\frac{4\pi\times 10^{-7}\times 2.9\times 5.3}{2\pi 0.11}\\ =2.7945\times 10^{-5}\ N

The magnitude of force per unit length of one wire on the other is 2.7945\times 10^{-5}\ N and the direction is away from one another

F_{12}=F_{21}=\frac{\mu_0 i_1i_2}{2\pi r}\\ =\frac{4\pi\times 10^{-7}\times 2.9\times 5.3}{2\pi 0.11}\\ =2.7945\times 10^{-5}\ N

The magnitude of force per unit length of one wire on the other is 2.7945\times 10^{-5}\ N and the direction is towards each other.

7 0
3 years ago
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