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eduard
3 years ago
13

PLEASE HELP ME

Physics
2 answers:
KATRIN_1 [288]3 years ago
6 0

B.Low levels of fecal coliform

posledela3 years ago
5 0
Low levels of fecal coliform
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What does this mean Atoms and elements are the basic back bone of the universe .
il63 [147K]
It means every thing is made out of Atoms and some things are element componds so elements are the "backbone" of the compounds.
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3 years ago
Consider an unknown charge that is released from rest at a particular location in an electric field so that it has some initial
sineoko [7]

Answer:

b)

Explanation:

If the charge is released at rest in an electric field, it will move along the electric field, going to regions of higher electric potential if it is a negative charge (against the field direction) and towards lower potential regions if it is positive (along the field). This means that the charge will gain kinetic energy, energy that only can come from a decrease in the electric potential energy.

For a positive charge: ΔEp = q*ΔV < 0 (as ΔV < 0)

For a negative charge: ΔEp = (-q) *ΔV < 0 (as ΔV > 0)

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3 years ago
Alexandra knows that the atomic number of the element potassium, K, is 19. She also knows that one particular isotope of potassi
fiasKO [112]
I believe the answer is 58 but I’m not sure
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3 years ago
A light bulb dissipates 100 Watts of power when it is supplied a voltage of 220 volts.
ycow [4]

Given Information:

Power = P = 100 Watts

Voltage = V = 220 Volts

Required Information:

a) Current = I = ?

b) Resistance = R = ?

Answer:

a) Current = I = 0.4545 A

b) Resistance = R = 484 Ω

Explanation:

According to the Ohm’s law, the power dissipated in the light bulb is given by

P = VI

Where V is the voltage across the light bulb, I is the current flowing through the light bulb and P is the power dissipated in the light bulb.

Re-arranging the above equation for current I yields,

I = \frac{P}{V}  \\\\I = \frac{100}{220} \\\\I = 0.4545 \: A \\\\

Therefore, 0.4545 A current is flowing through the light bulb.

According to the Ohm’s law, the voltage across the light bulb is given by

V = IR

Where V is the voltage across the light bulb, I is the current flowing through the light bulb and R is the resistance of the light bulb.

Re-arranging the above equation for resistance R yields,

R = \frac{V}{I} \\\\R = \frac{220}{0.4545} \\\\R = 484 \: \Omega

Therefore, the resistance of the bulb is 484 Ω

3 0
3 years ago
Read 2 more answers
Narysuj wykres zależności szybkości od czasu i drogi od czasu jeśli ciało porusza się ruchem jednostajnym z szybkością 45 m/s.
murzikaleks [220]
Lett me come back imma translate this... and then ill come to help
7 0
3 years ago
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