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3 years ago

8

2. A stone is thrown horizontally at a speed of 6.0 m/s from the top of a cliff 78.4 m high.

1 answer:

Ostrovityanka [42]3 years ago

3 0

Answer:

a) 8 seconds if you are using earth's gravity.

b) 48m if the velocity does not change

c) 9.8m/s

Explanation:

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When throwing curveballs in baseball, is it important to have air hit the ______ part of the ball.

Licemer1 [7]

Answer: A (smooth)

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3 years ago

Read 2 more answers

Physics conversion <br> Convert 300 cm/min^2 into m/s^2 <br> Please give a thorough explanation!

ANTONII [103]

Answer:

8.33×10⁻⁴ m/s²

Explanation:

There are 100 cm in 1 m, and 60 s in 1 min.

300 cm/min² × (1 m / 100 cm) × (1 min / 60 s)² = 8.33×10⁻⁴ m/s²

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3 years ago

Gold has a specific heat of 0.130 J/g*C. If 195 joules of heat are added to 15 grams of gold how much does the temperature of th

Anna71 [15]

The correct answer to the question is : $100\ ^0C$

EXPLANATION :

As per the question, the specific heat of gold is given as c = $0.130\ J/g^0C$

The heat given to the gold dQ = 195 J

The mass of the gold is given as m = 15 gram.

We are asked to calculate the change in temperature.

Let the change in temperature is dT.

We know that dQ = mcdT

$dT=\ \frac{dQ}{mc}$

$=\ \frac{195}{15\times 0.130}$

$=\ 100\ ^0C$ [ANS]

Hence, the change in temperature is 100 degree celsius.

5 0

3 years ago

The diver is on a board3.00m above the water. She jumps straight up at 3.25m/s. How many seconds later does she hit the water.

tigry1 [53]

Speed =distance/time
3.25=3.00/time
3.25xt=3.00
t=3/3.25
s=0.9s

5 0

4 years ago

A circular loop of wire has radius of 9.50 cmcm. A sinusoidal electromagnetic plane wave traveling in air passes through the loo

m_a_m_a [10]

Answer:

The induced emf is $\epsilon = 0.1041 \ V$

Explanation:

From the question we are told that

The radius of the circular loop is $r = 9.50 \ cm = 0.095 \ m$

The intensity of the wave is $I = 0.0215 \ W/m^2$

The wavelength is $\lambda = 6.90\ m$

Generally the intensity is mathematically represented as

$I = \frac{ c * B^2 }{ 2 * \mu_o }$

Here $\mu_o$ is the permeability of free space with value

$\mu_o = 4 \pi *10^{-7} N/A^2$

B is the magnetic field which can be mathematically represented from the equation as

$B = \sqrt{ \frac{ 2 * \mu_o * I }{ c} }$

substituting values

$B = \sqrt{ \frac{ 2 * 4\pi *10^{-7} * 0.0215 }{ 3.0*10^{8}} }$

$B = 1.342 *10^{-8} \ T$

The area is mathematically represented as

$A = \pi r^2$

substituting values

$A = 3.142 * (0.095)^2$

$A = 0.0284$

The angular velocity is mathematically represented as

$w = 2 * \pi * \frac{c}{\lambda }$

substituting values

$w = 2 * 3.142 * \frac{3.0*10^{8}}{ 6.90 }$

$w = 2.732 *10^{8} rad \ s^{-1}$

Generally the induced emf is mathematically represented as

$\epsilon = N * B * A * w * sin (wt )$

At maximum induced emf $sin (wt) = 1$

So

$\epsilon = N * B * A * w$

substituting values

$\epsilon = 1 * 1.342 *10^{-8} * 0.0284 *2.732 *10^{8}$

$\epsilon = 0.1041 \ V$

7 0

3 years ago