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garik1379 [7]
3 years ago
8

2. A stone is thrown horizontally at a speed of 6.0 m/s from the top of a cliff 78.4 m high.

Physics
1 answer:
Ostrovityanka [42]3 years ago
3 0

Answer:

a) 8 seconds if you are using earth's gravity.

b) 48m if the velocity does not change

c) 9.8m/s

Explanation:

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The answer is A stretched rubber band
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A Ferris wheel car is moving in a circular path at a constant speed. Is the car accelerating?
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No it is not because it’s moving at a constant speed
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How many meters are in a gigameter?
gladu [14]

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1 gigameter = 1e+9 meter

7 0
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The box leaves position x=0x=0 with speed v0v0. The box is slowed by a constant frictional force until it comes to rest at posit
SpyIntel [72]

Answer:

Magnitude of the Frictional force = (mv₀²)/2x₁

Explanation:

For the frictional force to stop the box, it has to produce the deceleration of the box; thereby being the opposing force to the box's motion.

According to Newton's first law of motion

Frictional force = (mass of the box) × (deceleration experienced by the box)

Let the mass of the box be m

Then,

Frictional force = ma

Then we can obtain the deceleration using the equations of motion

v² = u² + 2ax

u = Initial velocity = v₀ m/s

v = Final velocity = 0 m/s (since the box comes to rest at the end)

x = horizontal distance covered = (x₁ - x₀) = x₁ (since x₀ = 0)

a = ?

v² = u² + 2ax

0 = (v₀)² + 2ax₁

2ax₁ = - v₀²

a = - (v₀²)/(2x₁) (minus sign, because it's a deceleration)

Magnitude of the Frictional force = ma = (mv₀²)/2x₁

4 0
3 years ago
A 6 kg object falls 10 m. The object is attached mechanically to a paddle-wheel which rotates as the object falls. The paddle-wh
maksim [4K]

Answer:16.234^{\circ}C

Explanation:

Given

Mass of object (m)=6 kg

falling height(h)=10 m

mass of water(m_w)=600 gm

temperature of water =15

specific heat of water =4.186 j/g-^{\circ}C

Let T be the Final Temperature of water

Here Object Potential Energy is converted into Heat energy which will be absorbed by water

Potential Energy(P.E.)=mgh=6\times 9.81\times 10=588.6 J

Heat supplied=m_wc(\Delta T)

H.E.=600\times 4.186\times (T-16)

588.6=2511.6\times (T-16)

T-16=0.234

T=16.234^{\circ}C

This is not an efficient way of heating water as there is only0.234^{\circ}Cincrease in temperature.

5 0
3 years ago
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