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3 years ago

When is the pressure of the man on the ground more – lying position or standing position? Explain.

Physics

1 answer:

Dmitrij [34]3 years ago

3 0

It is without a doubt in standing position!
“I will explain if u ask”
(Please mark brainlest if I helped u a bit)

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you arrive at an intersection with traffic lights that arent working because of a power outage .what do you do

ElenaW [278]

Use it as a four way stop.

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3 years ago

Read 2 more answers

After combining components of two vectors to be added, it was found that the resultant vector has an x-component of -177 cm and

3241004551 [841]

The angle measured counterclockwise from the positive x-axis is θ = 50.4°

<h3>How to get the angle correspondent to a vector?</h3>

Here we know that the vector is:

V = < -177 cm, -214 cm>

To get the correspondent angle for this vector, we can think that this is the hypotenuse of a right triangle, such that the y-component and x-component are the cathetus.

Then, to get the angle (measured counterclockwise from the positive x-axis) is given by:

Tan(θ) = (opposite cathetus)/(adjacent cathetus)

Tan(θ) = (-214cm)/(-177 cm)

Using the inverse tangent function we get:

Atan(Tan(θ)) = Atan((-214cm)/(-177 cm))

θ = 50.4°

So the angle is 50.4°

If you want to learn more about vectors, you can read:

brainly.com/question/3184914

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2 years ago

A flat screen tv uses 120 watts. How much energy is used up if it is left on for 15 min?

xeze [42]

Answer:

Explanation:

8 0

3 years ago

The index of refraction of the first medium must be greater than the index of refraction of the second medium for total internal

laiz [17]

I think it’s true but I’m not really sure

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3 years ago

When a cricket ball is thrown vertically upwards, it reaches a maximum height of 15 metres. (a) What was the initial speed of th

Gelneren [198K]

Answer:

The velocity of the cricket ball is 17.32 m/s

Time is taken by the ball to reach the highest point = 0.8660 seconds

Explanation:

The cricket ball can be seen and treated as a projectile in this case

The maximum height attained by a projectile in motion can be calculated using the formula:

$h = \frac{v^2 sin^2 \theta }{2g}$

In any projectile problem, once we know see that the object was released vertically upwards, we need to know that this means that the angle of projection is 90 degrees, and sin 90 is = 1

hence, h will be modified to become

$h = \frac{v^2 }{2g}$

$v = \sqrt{2gh}$

We are given that h = 15m and g = 10m/s2

$v = \sqrt{2 \times 10 \times 15} = 17.32m/s$

The velocity of the cricket ball is 17.32 m/s

B. We can get the time it took to reach the highest point by dividing

time = distance/speed

Time = 15/17.32 = 0.8660 seconds

6 0

3 years ago