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Tomtit [17]
3 years ago
6

When is the pressure of the man on the ground more – lying position or standing position? Explain.

Physics
1 answer:
Dmitrij [34]3 years ago
3 0
It is without a doubt in standing position!
“I will explain if u ask”
(Please mark brainlest if I helped u a bit)
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Calculate the energy released by the electron-capture decay of 5727Co. Consider only the energy of the nuclei (ignore the energy
erma4kov [3.2K]

Answer:

Explanation:

⁵⁷Co₂₇  + e⁻¹  =  ²⁷Fe₂₆

mass defect = 56.936296 + .00055 - 56.935399

= .001447 u

equivalent energy

= 931.5 x .001447 MeV

= 1.3479 MeV .

= 1.35 MeV

energy of gamma ray photons = .14  + .017

= .157 MeV .

Rest of the energy goes to neutrino .

energy going to neutrino .

= 1.35 - .157

= 1.193 MeV.

5 0
3 years ago
What is the action force of a flying bird?
kirill [66]
It is called the reaction force of a bird flying.
7 0
3 years ago
The table below shows a sample wavelength of each type of electromagnetic radiation, along with its frequency and energy.
trasher [3.6K]

Answer:

D lower energy waves is most likely the safest if one is exposed to.

5 0
3 years ago
Calculate the momentum of a 1800 kg elephant charging a hunter at a speed of 7.50 m/s.
liq [111]

The amount of movement, linear momentum, momentum or momentum is a physical quantity derived from a vector type that describes the movement of a body in any mechanical theory. In classical mechanics, the amount of movement is defined as the product of body mass and its velocity at a given time.

p= mv

Where,

m = mass

v = Velocity

Our values are given as,

m = 1800kg

v = 7.5m/s

Replacing we have that,

p = (1800)(7.5)

p = 13500kg\cdot m/s

Therefore the momentum is 13500kg\cdot m/s

8 0
3 years ago
A particle moves along line segments from the origin to the points (1, 0, 0), (1, 5, 1), (0, 5, 1), and back to the origin under
Kaylis [27]

Answer:

0 J

Explanation:

Since work done W = ∫F.dr and F(x, y, z)= z²i + 4xyj + 5y²k and dr = dxi + dyj + dzk

F.dr = (z²i + 4xyj + 5y²k).(dxi + dyj + dzk) = z²dx + 4xydy + 5y²dz

W = ∫F.dr = ∫z²dx + 4xydy + 5y²dz = z²x + 2xy² + 5y²z

We now evaluate the work done for the different regions

W₁ = work done from (0,0,0) to (1,0,0)

W₁ = {z²x + 2xy² + 5y²z}₀₀₀¹⁰⁰ = 0²(1) + 2(1)(0)² + 5(0)²(0) - [(0)²(0) + 2(0)(0)² + 5(0)²(0)] = 0 - 0 = 0 J

W₂ = work done from (1,0,0) to (1,5,1)

W₂ = {z²x + 2xy² + 5y²z}₁₀₀¹⁵¹ =   (1)²(1) + 2(1)(5)² + 5(5)²(1) - [0²(1) + 2(1)(0)² + 5(0)²(0)] =  1 + 50 + 125 - 0 = 176 J

W₃ = work done from (1,5,1) to (0,5,1)

W₃ = {z²x + 2xy² + 5y²z}₁₅₁⁰⁵¹ =   1²(0) + 2(0)(5)² + 5(5)²(1) - [(1)²(1) + 2(1)(5)² + 5(5)²(1)]  = 125 - (1 + 50 + 125) = 125 - 176 = -51 J

W₄ = work done from (0,5,1) to (0,0,0)

W₄ = {z²x + 2xy² + 5y²z}₁₅₁⁰⁰⁰ =   (0)²(0) + 2(0)(0)² + 5(0)²(0) - [1²(0) + 2(0)(5)² + 5(5)²(1)] = 0 - 125 = -125 J

The total work done W is thus

W = W₁ + W₂ + W₃ + W₄

W = 0 J + 176 J - 51 J - 125 J

W = 176 J - 176 J

W = 0 J

The total work done equals 0 J

4 0
3 years ago
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