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ivolga24 [154]
3 years ago
7

If element A has an ionic charge of +2 and element B has an ionic charge of -3, what will be the formula for the compound create

d by element A and element B?
A2B3

A3B2

AB2

impossible to determine without additional information
Chemistry
1 answer:
Softa [21]3 years ago
8 0
A3B2 because the oxidation numbers are the same as ionic charge just switch symbol and number. Then use the cross cross method and you get A3B2.
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Calculate the molarity of the two solutions. The first solution contains 0.550 mol of NaOH in 1.40 L of solution.
olya-2409 [2.1K]

Answer:

0.393 mol/L.

Explanation:

The following data were obtained from the question:

Number of mole of NaOH = 0.550 mol

Volume of solution = 1.40 L

Molarity of NaOH =.?

Molarity of a solution is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the molarity of the NaOH solution as follow:

Number of mole of NaOH = 0.550 mol

Volume of solution = 1.40 L

Molarity of NaOH =.?

Molarity = mole / Volume

Molarity of NaOH = 0.55 / 1.4

Molarity of NaOH = 0.393 mol/L

Thus, the molarity of the NaOH solution is 0.393 mol/L.

6 0
3 years ago
Determine the poh of a 0.227 m c5h5n solution at 25°c. The kb of c5h5n is 1.7 × 10-9.
Juliette [100K]

4.71

hope this helps!

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3 0
3 years ago
IF 500 mL of air contains 2.50x10^22 particles (atoms and molecules). how much particles do you inhale in one day if you breath
vaieri [72.5K]

Answer:

I think it is 0.00192

Explanation:

28.795705

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8 0
3 years ago
Choose the nonmetallic elements from the list. Check all that apply yttrium: oxygen: boron: polonium: argon: gallium: carbon:
BaLLatris [955]

Answer:

B, E, & G

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7 0
3 years ago
Read 2 more answers
How many moles are equal to 1.3 x 1024 atoms of aluminum?
marshall27 [118]

Answer:

<h3>The answer is 2.16 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{1.3 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 2.159468...

We have the final answer as

<h3>2.16 moles</h3>

Hope this helps you

8 0
3 years ago
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