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Nutka1998 [239]
4 years ago
12

A"car"initially"at"rest"experiences"a" constant"acceleration"along"a"horizontal" road."the"position"of"the"car"at"several" succe

ssive"equal"time"intervals"is" illustrated"here. between"which"adjacent"positions"is"the" change"in"kinetic"energy"of"the"car"the" greatest
Physics
1 answer:
marysya [2.9K]4 years ago
7 0

In the process of peppering the question with those forty (40 !) un-necessary quotation marks, you neglected to actually show us the illustration.  So we have no information to describe the adjacent positions, and we're not able to come up with any answer to the question.

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A block of mass 8 m can move without friction
nekit [7.7K]

Answer:

Let M1 = 8 kg and M2 = 34 kg

F = M a = (M1 + M2) a

F = M2 g     the net force accelerating the system

M2 g = (M1 + M2) a

a = M2 / (M1 + M2) g = 34 / (42) g = .81 g = 7.9 m/s^2

5 0
2 years ago
A wire of resistance 5.9 Ω is connected to a battery whose emf ε is 4.0 V and whose internal resistance is 1.2 Ω. In 2.9 min, ho
dexar [7]

Answer:

a) 390J

b) 322J

c) 68J

Explanation:

We need to calculate the power given by the battery. the power is given by:

P=V*I\\I=\frac{V}{R}\\I=\frac{4}{5.9+1.2}\\I=0.56A\\P=2.24W

Watts is J/s so:

E=P*t\\E=2.24\frac{J}{s}*2.9min*(60\frac{s}{min})=390J

The thermal energy in the wire is given by:

E_w=P_w*t\\P_w=I^2*R_w=0.56^2*5.9=1.85W\\E_w=1.85\frac{J}{s}*2.9min*(60\frac{s}{min})=322J

And the the dissipated thermal energy in the battery will be the remainig energy:

E_b=E-E_w\\E_b=390-322=68J

4 0
4 years ago
As a laudably skeptical physics student, you want to test Coulomb's law. For this purpose, you set up a measurement in which a p
monitta

Answer:

force F = 1.66 × 10^{-13} N

Explanation:

given data

proton and an electron = 865 nm

solution

we get here force that is express as

force F = k q1 q2 ÷ r²      ......................1

put here value and we get

force F = 9 × 10^{9} × \frac{1.6\times (10^{-19})^{2}}{865 \times (10^{-9})^{2}}    

force F = 1.66 × 10^{-13} N

4 0
3 years ago
What frequency is received by the ambulance after reflecting from a wall near the person watching the oncoming ambulance (as in
ElenaW [278]

Answer:

f=896Hz

Explanation:

Given data

Vs(speed of the ambulance)={(104 km/h)*(1000m*(1 h/3600)}=28.9m/s

f(frequency of the ambulance siren)=821 Hz

v(speed of sound)=345 m/s

Vo(speed of the observer)=0 m/s

To find

f(The ambulance is approaching the person)

Solution

From Doppler effect

f^{i}=(\frac{v+v_{o} }{v-v_{s} })f

As the ambulance approaches the we assign a positive sign for speed "vs" of the ambulance

So

f^{i}=(\frac{v+0}{v-(+v_{s}) } )f\\f^{i}=(\frac{v}{v-v_{s} } )f

Substitute the values from given data

f^{i}=(\frac{345m/s}{345m/s-28.9m/s} )821Hz\\f^{i}=896Hz

5 0
3 years ago
Which explanation best describes a wave?
maw [93]
Is the energy contained in the particles of a medium
5 0
3 years ago
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