Answer:
A.
1. when the butter was placed on the spoon it slowly started to boil then began to melt.
2.the order was to heat the bowl, let it boil, then place the butter in.
3.The heat got from the water to the butter by placing it on the spoon then physically moving it into the hot bowl.
4.objects that do not conduct heat are called insulators.
B.
1. When the ice cube got placed into the water it immediately melted.
2.the water from the ice cube to the warm water as soon as it got laced it immediately melted.
3. the heat flowed straight up which made the ice melt really fast.
TABLE A: when I placed the butter in it melted a little bit slower than the ice cube but it still melted very fast.
TABLE B: when I put the colored one in the color slowly dissolved and pushed the color to the middle and the cube melted.
TABLE C: room temp water:75 degrees
cold water:50
hot water:315 degrees
TABLE D: when I blew out the candle the flame went but the smoke started to rise up.
TABLE E: the small beaker heated up quicker and I observed that the less amount of mass the faster it will heat up.
TABLE F: the black piece of paper heated up quicker and I believe its because the darker color the more mount of heat is attracted.
Explanation: I HOPE THIS HELPED! BRAINLESS?
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The value of each resistor is 23.51 ohms.
<h3>
Value of each resistor</h3>
The value of each resistor is calculated as follows;
R₁ = R₂ = R₃ = R
Total resistance, Rt = 3R
V = IRt
V = I(3R)
R = V/3I
R = (67)/(3 x 0.95)
R = 23.51 ohms
Thus, the value of each resistor is 23.51 ohms.
Learn more about resistor here: brainly.com/question/24858512
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Answer:
75%
Explanation:
We'll begin by calculating the final volume of the gas. This can be obtained as follow:
Initial volume (V₁) = V
Initial temperature (T₁) = T
Initial pressure (P₁) = P
Final pressure (P₂) = 2P
Final temperature (T₂) = ½T
Final volume (V₂) =?
P₁V₁/T₁ = P₂V₂/T₂
PV/T = 2P × V₂ / ½T
Cross multiply
T × 2P × V₂ = PV × ½T
T × 2P × V₂ = PV × ½T
Divide both side by T × 2P
V₂ = (PV × ½T) / T × 2P
V₂ = ¼V
Next, we shall determine the absolute change in the volume of the gas. This can be obtained as follow:
Initial volume (V₁) = V
Final volume (V₂) = ¼V
Absolute change in volume |ΔV| =?
|ΔV| = |V₂ – V₁|
|ΔV| = |¼V – V|
|ΔV| = |0.25V – V|
|ΔV| = 0.75V
Finally, we shall determine percentage change in the volume of the gas. This can be obtained as follow:
Initial volume (V₁) = V
Absolute change in volume |ΔV| = 0.75V
Percentage change =?
Percentage change = |ΔV| / V × 100
Percentage change = 0.75V / V × 100
Percentage change = 0.75 × 100
Percentage change = 75%
Thus, the percentage change in the volume of the gas is 75%
