Gravity is 9.8 m/s² means means every second distance travelled
increases by the distance in the previous second plus an extra 9.8m
during last second it fell 38m
previous second dist = 38 - 9.8m = 28.2
previous second = 28.2 - 9.8m = 18.4m
distance left = 18.4 - 9.8m = 8.6m
(so actually less than a second as it only travelled 8.6m)
total distance h = 38 + 28.2 + 18.4 + 8.6 = 93.2m
hope this is what is required
1. Inside a circle described by a point charge at its center will not be uniform field as a point charge field will change with distance where as we move away the field strength will go down.
2. between parallel plates of equal charge and equal magnitude will have zero electric field because both plates are of same charge so electric field of both plates will cancel each other.
3. inside a circle described by identical, evenly-spaced point charges around the circumference field will be zero as all charges are distributed uniformly and they cancel the field effect of each other.
4. between parallel plates of equal charge and opposite magnitude field will be nearly uniform as the two charges are opposite in nature and equal in magnitude so the effect will be added.
So answer of the above will be between parallel plates of equal charge and opposite magnitude
I don’t understand the question
Answer: a) Cnew=Cinitial ; b) λouter new= 2*λ outer initial
Explanation: In order to explain this question we have to take into account the expression of teh cylinder capacitor given by:
C/L= (2*π*εo)/ln (b/a)= where b and a are the outer and inner radius, respectively. L is the length of the capacitor.
As you can se this formule depents of geometrical characateristics of the capacitor.
The capacitance is the same after change the densities of charge.
On the other hand,
The new charge in each cylinder ( inner and outer) is determined
The new potential is 2 times the initial one so
V new= 2* Vinitial
Also we know that
Vnew= Q/C= λnew*L/C; C= constant
using this formule and considering that V new is doubled then the charge per one meter length, is also doubled .
This is as follow:
Vnew= λnew*L/C=
λnew = (2*Vinitial)* C/L= 2 (λ initial)
Then λouter new = 2* λouter initial
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