Answer:
A
Explanation:
The Charles law states that the volume of an ideal gas increases when temperature is increased under constant pressure. The pressure inside the balloon is always equal to the atmospheric pressure. Therefore answer A demonstrate the Charles law.
Answer:
2.1 x 10^6 J
Explanation:
Long story short, just think of the units of every question and then think again which unit needs to be cancelled out inorder for you to get the one which is asked.
the formula to calculate heat energy is Q = mcT
T - change in temperature
m - mass of substance
c - specific heat capacity of substance
the change in temperature is already given but you will need to change it to kelvin inorder for it to get cancelled out with the unit under specific heat capacity which is J/k gram. Tk = Tc + 273 = 3.32 + 273.15 = 276.47K
now keep in mind that c varies from substance to substance.
in this case it is 4.18J/k.g for water.
you will also need to convert the mass from kilograms to grams so it can cancel out as well. so now let's multiply 1.82 kg by a 1000 so that we can convert it to grams. which is equivalent to 1820g
now it's all set...let's substitute the values we dag out in the Heat formula Q = mcT
=1820g x 4.18Jk.g x 276.47K = 2.1 x 10^6J
so this is out final answer for heat required to raise the temperature of water by the particularly given quantity.
peace to you.
If the net forced is doubled , the acceleration would also be doubled. F= M,A,F/M = a, 2F/M=2A. sorry if that doesn’t make sense i tried
For the rocket engine a lean or excessively rich air-fuel ratio will lead to a compromise in the power output and ultimately the altitude the rocket will reach. Hence which ever the ratio the altitude is greatly affected, unless the ideal ratio is archived.
The air-fuel ratio is the ratio of the amount of air need to burn a part of fuel in a combustion cycle, the ratio is basically a compromise between fuel economy and optimum power output.
For a gasoline engine for example, the ideal air-fuel mixture of 14.7 parts air to 1 part fuel.
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