<span>The chemical mixture that composes our atmosphere is called Synopt.</span>
Answer:
4.42 × 10⁻³⁷ m
Explanation:
Step 1: Given and required data
- Mass of the body (m): 1 kg
- Velocity of the body (v): 1500 m/s
- Planck's constant (h): 6.63 × 10⁻³⁴ J.s
Step 2: Calculate the de Broglie wavelenght (λ) of the body
We will use de Broglie's equation.
λ = h / m × v
λ = (6.63 × 10⁻³⁴ J.s) / 1 kg × (1500 m/s) = 4.42 × 10⁻³⁷ m
Answer:
Water and carbon dioxide combine to form glucose and oxygen.
I hope this helped :)
We have Boltzmann's equation S = k ln W
Boltzmann's constant k = 1.381 x 10^-23 J/K
W = Number of absorption sites
At W = 484, Entropy S1 = 1.381 x 10^-23 ln 484 = 8.537 x 10^-23 J/K
At W = 729, Entropy S2 = 1.381 x 10^-23 ln 729 = 9.103 x 10^-23 J/K
Change of Entropy = S2 - S1 = 0.566 x 10^-23 J/K
Answer:
Solution given:
heat[Q]=?
temperature [T]=0.64°C
specific heat capacity [c]=0.880 J/g °C
mass[m]=3g
we have
Q=mcT=3*0.880*0.64°=1.69Joule
<u>the</u><u> </u><u>required</u><u> heat </u><u>is</u><u> </u><u>1.69</u><u>Joule</u><u>.</u>