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NeX [460]
3 years ago
7

Which branch of science involves the study of matter and energy

Physics
2 answers:
Olin [163]3 years ago
6 0
Physics<span> is a natural science that involves the study of matter and its motion through space time, along with related concepts such as energy and force.</span>
Klio2033 [76]3 years ago
6 0

Answer:

Physics

Explanation:

Physics is the branch of science that handles the study of different phenomena in the nature. The four pillars are thermodynamic, classical mechanics, electromagnetism and quantum mechanics.

Thermodynamics studies the temperature of an object. Classical mechanics studies the cinematic and dynamic of bodies. The electromagnetism studies the electric and magnetic properties of the objects. And quantum mechanics studies the behavior of matter in a macroscopic scale.

In all of the cases mentioned above, energy is present in its different forms (mechanic energy, kinetic energy, potential energy).

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A 10 kg rock that has been dropped from a 60 meter high cliff experiences an average force of air resistance of 30 N. Calculate
lesya692 [45]

Answer:

4086 J

Explanation:

The potential energy is transformed to kinetic energy less the frictional energy. Potential energy= mgh where m represent mass, g is acceleration due to gravity and h is the height of cliff

Since we have force of air resistance, work done due to air resistance will be product of force and distance

mgh-Fh= 0.5mv^{2}= KE

Substituting 10 Kg for m, 9.81 for g and 60 m for F then the kinetic energy at the bottom will be

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8 0
3 years ago
An electric furnace is to melt 40 kg of aluminium/hour. The initial temperature of aluminium is 32°C. Given that aluminium has s
gizmo_the_mogwai [7]

Answer:

Part a)

P = 13.93 kW

Part b)

R = 8357.6 Cents

Explanation:

Part A)

heat required to melt the aluminium is given by

Q = ms\Delta T + mL

here we have

Q = 40(950)(680 - 32) + 40(450 \times 10^3)

Q = 24624 kJ + 18000 kJ

Q = 42624 kJ

Since this is the amount of aluminium per hour

so power required to melt is given by

P = \frac{Q}{t}

P = \frac{42624}{3600} kW

P = 11.84 kW

Since the efficiency is 85% so actual power required will be

P = \frac{11.84}{0.85} = 13.93 kW

Part B)

Total energy consumed by the furnace for 30 hours

Energy = power \times time

Energy = 13.93 kW\times 30 h

Energy = 417.9 kWh

now the total cost of energy consumption is given as

R = P \times 20 \frac{Cents}{kWh}

R = 417.9 kWh\times  20 \frac{cents}{kWh}

R = 8357.6 Cents

3 0
3 years ago
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