pH is referred to as the scale to describe the hydronium ion concentration of a
solution. It is used to measure the acidity or basicity of a solution. pH of an acidic solution is less than 7, a neutral solution is 7, and a basic solution is greater than 7.
pH can be calculated using the formula:
![pH = - log [H_{3}O^{+}]](https://tex.z-dn.net/?f=%20pH%20%3D%20-%20log%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%20%20)
Given the pH of solution is 3.2.
Finding out the concentration of hydronium ion from pH.
![pH = - log[H_{3}O^{+}]](https://tex.z-dn.net/?f=%20pH%20%3D%20-%20log%5BH_%7B3%7DO%5E%7B%2B%7D%5D)
![3.2 = - log [H_{3}O^{+}]](https://tex.z-dn.net/?f=%203.2%20%3D%20-%20log%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%20%20)
![[H_{3}O^{+}] = 10^{-3.2}](https://tex.z-dn.net/?f=%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%2010%5E%7B-3.2%7D%20%20%20%20)
![[H_{3}O^{+}] = 6.3 * 10^{-4} M](https://tex.z-dn.net/?f=%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%20%20%206.3%20%2A%2010%5E%7B-4%7D%20M%20%20)
Therefore, the hydronium ion concetration of the solution is 
Percentage yield=(actual yield/theoretical yield) x 100%
= (45/50) x 100%
= 90%
Answer:
904.8 kg / m3
Explanation:
19.0 kg/0.021 m^3 = 904.761905 kg / m3
They create salt when put together
the balanced equation for the formation of ammonia is
N₂ + 3H₂ ---> 2NH₃
molar ratio of N₂ to NH₃ is 1:2
mass of N₂ reacted is 8.0 g
therefore number of N₂ moles reacted is - 8.0 g / 28 g/mol = 0.286 mol
according to the molar ratio,
1 mol of N₂ will react to give 2 mol of NH₃, assuming nitrogen is the limiting reactant
therefore 0.286 mol of N₂ should give - 2 x 0.286 mol = 0.572 mol of NH₃
therefore mass of NH₃ formed is - 0.572 mol x 17 g/mol = 9.72 g
a mass of 9.72 mol of NH₃ is formed
