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Sergeu [11.5K]
3 years ago
13

Iron is obtained by reducing iron (III) oxide using the gas carbon monoxide. The reaction is

Chemistry
1 answer:
ivann1987 [24]3 years ago
7 0
A. iron(III) oxide + Carbon-monoxide -> Iron + Carbon-di-oxide.
b.56*2 +16*3
c.Moles=mass(g) / Mr which is 3200/160
d. 2 moles
e.2 moles
f. Moles x Mr = mass so, 20 x 112=2240g
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In atomic mass units, what is the average atomic mass of the atoms that make up boron (B)?
Annette [7]
Atomic mass is the decimal number that is on the periodic table...

Boron's atomic mass is 10.81
5 0
3 years ago
Calculate the answer. Express it in scientific notation and include the correct number of significant figures. (12 x 104 ) x (5
ipn [44]

Answer:

Explanation:

(12 x 104 ) x (5 x 10-²) = 6 x 10 ³ 6 x 105 6.0x10²

1.  (12 x 104 ) = 1248 or 1.248 x 10^3

2.  (1.248 x 10^3)(5 x 10^-2) = 6.240 x 10^1 or 60 rounded to 1 sig fig

I don't understand "= 6 x 10 ³ 6 x 105 6.0x10² "

6 0
1 year ago
HELP WITH CHEMISTRY PLEASE!
maria [59]

Answer:

1) 1.52 atm.

2) 647.85 K.

3) 20.56 L.

4) 1.513 mole.

5) 254.22 K = -18.77 °C.

Explanation:

  • In all this points, we should use the law of ideal gas to solve this problem: PV = nRT.
  • Where, P is the pressure (atm), V is the volume (L), n is the number of moles, R is the general gas constant (0.082 L.atm/mol.K), and T is the temperature (K).

1) In this point; n, R, and T are constants and the variables are P and V.

P and V are inversely proportional to each other that if we have two cases we get: P1V1 = P2V2.

<u><em>In our problem:</em></u>

P1 = ??? <em>(is needed to be calculated) </em>and V1 = 45.0 L.

P2 = 5.7 atm and V2 = 12.0 L.

Then, the original pressure (P1) = P2V2 / V1 = (5.7 atm x 12.0 L) / (45.0 L) = 1.52 atm.


2) In this case, n and R are the constants and the variables are P, V, and T.

P and V are inversely proportional to each other and both of them are directly proportional to the temperature of the gas that if we have two cases we get: P1V1T2 = P2V2T1.

<u><em>In our problem:</em></u>

P1 = 212.0 kPa, V1 = 32.0 L, and T1 = 20.0 °C = (20 °C + 273) = 293 K.

P2 = 300.0 kPa, V2= 50.0 L, and T2 = ??? <em>(is needed to be calculated) </em>

Then, the temperature in the second case (T2) = P2V2T1 / P1V1 = (300.0 kPa x 50.0 L x 293 K) / (212.0 kPa x 32.0 L) = 647.85 K.


3) In this case, P, n and R are the constants and the variables are V, and T.

V and T are directly proportional to each other that if we have two cases we get: V1T2 = V2T1.

<u><em>In our problem:</em></u>

V1 = 25.0 L and T1 = 65.0 °C + 273 = 338 K.

V2 = ??? <em>(is needed to be calculated) </em> and T2 = 5.0 °C + 273 = 278 K.

Herein, there is no necessary to convert T into K.

Then, the volume in the second case (V2) = V1T2 / T1 = (25.0 L x 278 °C) / (338 °C) = 20.56 L.


4) We can get the number of moles that will fill the container from: n = PV/RT.

P = 250.0 kPa, we must convert the unit from kPa to atm; <em><u>101.325 kPa = 1.0 atm</u></em>, then P = (1.0 atm x 250.0 kPa) / (101.325 kPa) = 2.467 atm.

V = 16.0 L.

R = 0.082 L.atm/mol.K.

T = 45 °C + 273 = 318 K.

Now, n = PV/RT = (2.467 atm x 16.0 L) / (0.082 L.atm/mol.K x 318 K) = 1.513 mole.


5) In this case, V, n and R are the constants and the variables are P, and T.

P and T are directly proportional to each other that if we have two cases we get: P1T2 = P2T1.

<u><em>In our problem:</em></u>

P1 = 2200.0 mmHg and T1 = ??? <em>(is needed to be calculated) </em>.

P2 = 2700.0 mmHg and T2 = 39.0 °C + 273 = 312.0 K.

Herein, there is no necessary to convert P into atm.

Then, the temperature in the morning (T1) = P1T2 / P2 = (2200.0 mmHg x 312.0 K) / (2700.0 mmHg) = 254.22 K = -18.77 °C.

6 0
3 years ago
Read 2 more answers
Have an infinite number of significant figures
vovikov84 [41]
The answer is: Non-zero
7 0
3 years ago
____H3PO4 + ____ KOH --&gt; ______K3PO4 + ____H2O can someone please balance that chemical equation?
Murrr4er [49]

Answer:

H3PO4 + 3KOH ----> K3PO4 + 3H2O

Explanation:

The valency of K element is + 1 while that of PO4 compound is -3

Hence, at least 3 K atoms are needed to combine with PO4 to form K3PO4 compound.

Hence, the revised equation will be

H3PO4 + 3KOH ----> K3PO4 + 3H2O

Now, the number of atoms and charges of each element is a given equation are equal on both the left and right hand side.

6 0
2 years ago
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