Answer: balanced reaction equation
C8H18(g) + 25/2 O2(g) ---------> 8CO2(g) + 9H2O(l)
Explanation:
Part A- coefficients
1, 25/2,8,9
Part B
Oxygen is the limiting reactant
Part C
If 1 mole of octane produced 9 moles of water from the balanced reaction equation
0.28 moles of octane will produce 0.28×9= 2.52 moles of water
Part D
If 12.5 moles of oxygen reacts with 1 mole of octane
0.63 moles of oxygen will react with 0.63/12.5=0.0504moles of octane
Amount of octane left= 0.280-0.0504=0.2296 moles
V=84.0 mL = 84.0 cm³
m=609.0 g
p=m/v
p=609.0/84.0=7.25 g/cm³
Answer:
3.2 g of O₂
Solution:
This reaction is for the formation of Potassium Superoxide, The reaction is as follow,
K + O₂ → KO₂
First let us confirm that either the given amount of Potassium produces the given amount of Potassium oxide or not,
So,
As,
39.098 g (1 mole) K produced = 71.098 g of K₂O
So,
3.91 g of K will produce = X g of K₂O
Solving for X,
X = (3.91 g × 71.098 g) ÷ 39.098
X = 7.11 g of K₂O
Hence, it is confirmed that we have selected the right equation,
So,
As,
39.098 g of K required = 32 g of O₂
So,
3.91 g of K will require = X g of O₂
Solving for X,
X = (3.91 g × 32 g) ÷ 39.098 g
X = 3.2 g of O₂
The bonding of two atoms will most likely occur if A. a more stable state can result from the union.
Otherwise, there would be no point in making two atoms bond.
