Answer:) Calculate the acceleration of a skier heading down a. 10.0º slope, assuming the coefficient of friction for waxed.
Explanation:
I believe this is right I'm not sure so if I'm rong let me know please.
The time per lap was calculated by measuring the time for seven laps and dividing the total time by seven.
total time
It is given that the precision is of 0.1 s. it means it is correct upto 1 place beyond decimal.
So, the actual value could vary from 457.800 s to 457.899 s i.e. the time per lap could be 65.400 s to 65.414 s
It means measured time 65.414 s has maximum error of 0.021%. Hence, the measured value is quite precise.
answer:
2.5 m/s²
Explanation:
120 km/h = 120 ÷ 3.6 = 100/3 ≈ 33 m/s
a = (v2 - v1)/∆t = (33m/s - 0)/ 13s = 33/13 m/s²≈ 2.5 m/s²
Explanation:
The given number is 1.30x10-5. We need to convert it into scientific notation. We know that, any no can be written in this form as follows :
...(1)
m is any real no and n is any integer
If we compare the given no with equation (1), then, we found that m = 1.3 and n = -5.
It means that the given no is already in scientific notation. It can be written as :