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4 years ago

You have $121 in a savings account and save $1 2

Mathematics

1 answer:

serious [3.7K]4 years ago

3 0

It will take 6 weeks for you and your friend to have the same balance.

First, you must set up your equation, with $x$ representing the amount of weeks

until you and your friend have the same balance.

$121+12x=91+17x$

Then, you must subtract 91 on both sides.

$30+12x=17x$

Next, subtract 12x on both sides.

$30=5x$

Finally, divide 5 on each side

$x=6$

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Explain to me in words how you would find the slope of this line and explain how you got your answer

Delvig [45]

Answer:

y=mx+b

Step-by-step explanation:

8 0

3 years ago

In the chart of accounts, each account number has two digits. The first digit indicates the major account group to which the acc

Eduardwww [97]

Answer:

The correct option is (b)

Step-by-step explanation:

Chart of accounts refers to listing or arranging various accounts for the ease of locating them. Listing is done based on the order of appearance beginning with balance sheet and then income statement.

The order starts with assets, followed by liabilities and stockholders' equity from the balance sheet and revenue and expenses from income statement.

So, the correct order is stated in option (b).

4 0

4 years ago

Read 2 more answers

F(x)=x^2 what is g(x)

Triss [41]

Answer: D

Step-by-step explanation:

Sometimes, it is hard to see which function fits g(x). We are given the point (4,1). Luckily, the point lies on g(x). We can plug in (4,1) into the g(x) equations and see which best fits.

A. Incorrect

$1=4(4)^2$

$1=4(16)$

$1\neq 64$

B. Incorrect

$1=\frac{1}{4} (4)^2$

$1=\frac{1}{4} (16)$

$1\neq 4$

C. Incorrect

$1=(\frac{1}{2}(4))^2$

$1=(2)^2$

$1\neq 4$

D. Correct

$1=(\frac{1}{4}(4))^2$

$1=(1)^2$

$1=1$

4 0

3 years ago

Can someone help me with this please :)))

Inessa [10]

Answer : 58 square units.

Tip : break the shape down into shapes you can easily find the area of.

I found the area of the two squares on the bottom
They are identical and are both 2 units tall and two units long giving, giving an area of 4, and since there are two of them you can multiply the are by two giving you 8
Next found the area of the remaining shape which is just a rectangle that excludes the two bottom squares which is 10 units long and 5 units tall multiplying to 50
50+8=58

7 0

2 years ago

Read 2 more answers

44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access

DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.

FileSystemLocked → ∀x Access(x, SystemMailbox)

(c)

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0

3 years ago