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garik1379 [7]
3 years ago
14

if a source of sound waves is rabidly approaching a person the sound heard by the person appears to have?

Physics
2 answers:
Romashka-Z-Leto [24]3 years ago
8 0

Answer:

have a frequency. higher than the frequency actually produced by the source.

Explanation:

solong [7]3 years ago
7 0

Answer:

If a source of sound waves is rapidly approaching a person, the sound heard by the person appears to have - a pitch lower than the original pitch.

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Use the following table of a school bus during morning pickups to calculate its average speed between 0h and 2.34h.
Gelneren [198K]

Answer:

Hi there, this image is your answer

3 0
3 years ago
A majorette in the Rose Bowl Parade tosses a baton into the air with an initial angular velocity of 2.5 rev/s. If the baton unde
oksian1 [2.3K]

Answer:

14 rev

Explanation:

w_{o} = initial angular velocity = 2.5 revs⁻¹

w = final angular velocity = 0.8 revs⁻¹

\alpha = Angular acceleration = - 0.2 revs⁻²

\theta = Angular displacement

Using the equation

w^{2} = w_{o}^{2} + 2 \alpha \theta\\0.8^{2} = 2.5^{2} + 2 (- 0.2) \theta\\ \theta = 14 rev

So the number of revolutions are 14

4 0
3 years ago
In general, how do you find the average velocity of any object falling in a vacuum?
irina [24]
In general, how do you find the average velocity of any object falling in a vacuum? (Assume you know the final velocity.) Multiply the final velocity by final time. 3. Calculate : Distance, average velocity, and time are related by the equation, d = v • t A
5 0
3 years ago
A water wheel rotates with a period of 2.26 s. If the water wheel has a radius of l.94 m,
Dafna11 [192]

Answer:

The correct answer is B)

Explanation:

When a wheel rotates without sliding, the straight-line distance covered by the wheel's center-of-mass is exactly equal to the rotational distance covered by a point on the edge of the wheel.  So given that the distances and times are same, the translational speed of the center of the wheel amounts to or becomes the same as the rotational speed of a point on the edge of the wheel.

The formula for calculating the velocity of a point on the edge of the wheel is given as

V_{r} = 2π r / T

Where

π is Pi which mathematically is approximately 3.14159

T is period of time

Vr is Velocity of the point on the edge of the wheel

The answer is left in Meters/Seconds so we will work with our information as is given in the question.

Vr = (2 x 3.14159 x 1.94m)/2.26

Vr = 12.1893692/2.26

Vr = 5.39352619469

Which is approximately 5.39

Cheers!

7 0
3 years ago
A 143 kg astronaut is floating in
Dima020 [189]

The recoil velocity of the astronaut is -0.070 m/s

Explanation:

We can solve this problem by using the principle of conservation of momentum: in fact, in absence of external forces, the total momentum of the astronaut-wrench system must be conserved.

At the beginning, their total momentum is zero:

p=0 (1)

Later, after the astronaut throws the wrench, the total momentum is

p=mv+MV (2)

where

m = 0.725 kg is the mass of the wrench

v = 13.8 m/s is the velocity of the wrench

M = 143 kg is the mass of the astronaut

V is the recoil velocity of the astronaut

Since momentum is conserved, (1) = (2), and so we can find V:

0=mv+MV\\V=-\frac{mv}{M}=-\frac{(0.725)(13.8)}{143}=-0.070 m/s

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

5 0
3 years ago
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