The mass of the bullet moving at the given values of velocity and kinetic energy is 6.4 × 10⁻⁴ kilogram.
<h3>What is Kinetic Energy?</h3>
Kinetic energy is simply a form of energy that a particle or object possesses due to its motion.
It is expressed as;
K = (1/2)mv²
Where m is mass of the object and v is its velocity.
Given the data in the question;
- Velocity of the bullet v = 970m/s
- Kinetic energy of the bullet K = 3.0 × 10³J = 3000kgm²/s²
- Mass of the bullet m = ?
We substitute our given values into the expression above.
K = (1/2)mv²
3000kgm²/s² = 0.5 × m × (970m/s)²
3000kgm²/s² = 0.5 × m × 940900m²/s²
3000kgm²/s² = m × 470450m²/s²
m = 3000kgm²/s² ÷ 470450m²/s²
m = 0.00064kg
m = 6.4 × 10⁻⁴kg
Therefore, the mass of the bullet moving at the given values of velocity and kinetic energy is 6.4 × 10⁻⁴ kilogram.
Learn more about kinetic energy here: brainly.com/question/12669551
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Answer:
V(c)' = 0.325 m/s
V(a)' = 2.19375 m/s
V(b)'' = 0.73125
Explanation:
See attachment for explanation.
Answer:
A) x4
Explanation:
Magnification is equal to image size divided by the actual size, or M = I/A.
The image size is the student's drawing, which is 28.8 cm, and the actual size is 7.2 cm. Divide them, and cancel out the units, and you should get:
28.8 cm/7.2 cm = 4