V(NaOH)=15 mL =0.015 L
C(NaOH)=0.1 mol/L
C(H₂SO₄)=0.05 mol/L
2NaOH + H₂SO₄ = Na₂SO₄ + 2H₂O
n(NaOH)=V(NaOH)C(NaOH)=2n(H₂SO₄)
n(H₂SO₄)=V(H₂SO₄)C(H₂SO₄)
V(NaOH)C(NaOH)=2V(H₂SO₄)C(H₂SO₄)
V(H₂SO₄)=V(NaOH)C(NaOH)/{2C(H₂SO₄)}
V(H₂SO₄)=0.015*0.1/{2*0.05}=0.015 L = 15 mL
Answer:The farming methods promoted by the California Ricelands Habitat Partnership are best described as beneficial to both farmers and wetland species because California Rice Commission and individual growers to further enhance the habitat [ value of California’s rice fields to waterbirds. This collective approach creates synergy for fully realizing the wildlife values in California rice
Answer:
244.76
Explanation:
The weight of grams by 1.82 moles of lithium carbonate would be: 134.481438 So we need to use this equation to find mass by grams m × g = ms Where m is for moles, g for grams, and ms for mass. So now we need use this equation: 1.82 × 134.481438 = ? 1.82 × 134.481438 = 244.75621716 244.75621716, rounded-up (to the nearest-tenths place) is 244.76. So now you have it! The mass of 1.82 moles of lithium carbonate is 244.76!
Answer:
The answer to your question is V2 = 23.52 l
Explanation:
Data
Volume 1 = V1 = 22.5 l
Pressure 1 = P1 = 734 mmHg
Volume 2 = V2 = ?
Pressure 2 = 702 mmHg
Process
To solve this problem use Boyle's law.
P1V1 = P2V2
-Solve for V2
V2 = P1V1 / P2
-Substitution
V2 = (734 x 22.5) / 702
-Simplification
V2 = 16515 / 702
-Result
V2 = 23.52 l
-Conclusion
If we diminish the pressure, the volume will be higher.
