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seropon [69]
3 years ago
12

How many liters of oxygen gas, at standard temperature and pressure, will react with 35.4 grams of calcium metal? Show all of th

e work used to solve this problem. 2Ca + O2 yields 2CaO
Chemistry
1 answer:
Margaret [11]3 years ago
5 0
Answer: 19.8 l


Explanation:

1) Chemical equation:

2Ca + O₂ → 2CaO


2) Mole ratios: 2 mol Ca : 1 mol O₂ : 2 mol CaO

3) Convert 35.4 g of Ca to moles:

n = mass in grams / molar mass = 35.4 g / 40.1 g/mol = 0.883 mol

4) Volume proportion: 1 mol of gas at STP = 22.4 l


1 mol at STP              0.883 mol at STP

--------------------- = ------------------------------

22.4 l                                      x

⇒ x = 0.883 mol × 22.4 l / 1 mol = 19.8 l ← answer
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Explanation:
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Oxidation number of Al on left hand side is zero, while than on right hand side in Al₂O₃ is +3. Means it has lost 3 electrons per one atom and six electrons per two atoms. Also, the oxidation number of O at left hand side in O₂ is zero, while that in Al₂O₃ it is -2 per atom and -6 per 3 atoms. 

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