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3 years ago

Two answer multiple choice-- please help!

Chemistry

1 answer:

ELEN [110]3 years ago

8 0

Answer:

Rate = K[NH₄⁺][NO₂⁻]

Explanation:

In kinetics studies of reaction, rate law is a mathematical expression that relates speed of reaction with concentrations of the reactants. For a reaction:

aA + nN → cC + dD

The rate law is expressed in terms of [A] and [B] as follows:

Rate = K[A]ᵃ[N]ⁿ

<em>Where K is rate constant.</em>

<em />

For the reaction:

NH4+ + NO2– ⟶ N2 + 2H2O

The rate law is:

<em>As was said in the problem, the rate is porportional to [NH₄⁺] and to [NO₂⁻]</em>

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svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = $62.364\text{ L. Torr }mol^{-1}K^{-1}$

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Putting values in above equation, we get:

$51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol$

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

$0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g$

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

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