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Alecsey [184]
3 years ago
14

The diagram shows the movement of air as a result of convection currents. At which point is the air at its highest density?

Physics
2 answers:
stellarik [79]3 years ago
6 0

When you bring two objects of different temperature together, energy will always be transferred from the hotter to the cooler object.  The objects will exchange thermal energy, until thermal equilibrium is reached, i.e. until their temperatures are equal.  We say that heat flows from the hotter to the cooler object.  Heat is energy on the move.  

Units of heat are units of energy.  The SI unit of energy is Joule.  Other often encountered units of energy are 1 Cal = 1 kcal = 4186 J, 1 cal = 4.186 J, 1 Btu = 1054 J.

Without an external agent doing work, heat will always flow from a hotter to a cooler object.  Two objects of different temperature always interact.  There are three different ways for heat to flow from one object to another.  They are conduction, convection, and radiation.

 

Hatshy [7]3 years ago
4 0

Answer: The answer is X.

Explanation: The air at the lowest point in the diagram is the most dense because it has cooled and sunk to the floor of the house.

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A projectile is launched with a horizontal velocity of 20 m/s and an initial vertical velocity of 20 m/s. What is the projectile
cestrela7 [59]

Answer:

Vertical acceleration 9.8 m/s² downward

Horizontal acceleration 0.0 m/s²

assuming no air resistance.

6 0
2 years ago
17. What is the speed of a race horse that runs<br> 1500 m in 125 s?
Hoochie [10]

Answer:

12 miles per second

Explanation:

6 0
3 years ago
Read 2 more answers
A 350-km-long high-voltage transmission line 2.00 cm in diameter carries a steady current of 1,010 A. If the conductor is copper
Masja [62]

Answer:

t = 47 years

Explanation:

To find the number of years in which the electrons cross the complete transmission, you first calculate the drift velocity of the electrons in the transmission line, by using the following formula:

v_d=\frac{I}{nAq}         (1)

I: current = 1,010A

A: cross sectional area of the transmission line = π(d/2)^2

d: diameter of the transmission line = 2.00cm = 0.02 m

n: free charge density = 8.50*10^28 electrons/m^3

q: electron's charge = 1.6*10^-19 C

You replace the values of all parameters in the equation (1):

v_d=\frac{1010A}{(8.50*10^{28}m^{-3})(\pi(0.02m/2)^2)(1.6*10^{-19}C)}\\\\v_d=2.36*10^{-4}\frac{m}{s}

with this value of the drift velocity you can calculate the time that electrons take in crossing the complete transmission line:

t=\frac{d}{v_d}=\frac{350km}{2.36*10^{-4}m/s}=\frac{350000m}{2.36*10^{-4}m/s}\\\\t=1,483,050,847\ s

Finally, you convert this value of the time to years:

t=1,483,050,847s*\frac{1\ year}{3.154*10^7s}=47\ years

hence, the electrons take around 47 years to cross the complete transmission line.

7 0
3 years ago
Calculate how much calories you have if you have 8 joule ? please:
goblinko [34]

Answer:

If you have 8 Joules of energy that means you have 1.912 calories.

Explanation:

As we know that one calorie is equal to 4.184 J. We need to calculate in 8 Joules of energy how many calories are present.

We know that,

For 1 calorie = 4.184 J

For ? = 8 Joules

To obtain calories in 8 Joules. Divide 8 by 4.184.

\text { Calorie }=\frac{\text { Joule }}{4.184}

\text { calorie }=\frac{8}{4.184}

calorie=1.912

Therefore, 8 J = 1.912 calorie.

5 0
3 years ago
A compression spring with a spring constant of 200 N/m catches a ball that's falling with
mrs_skeptik [129]

Answer:

distance of compression: 0.07071 m

Explanation:

\sf energy = \dfrac{1}{2} kx^2

\rightarrow \sf 0.5= \dfrac{1}{2} (200)x^2

\rightarrow \sf 0.5= (100)x^2

\rightarrow \sf 5\ *\ 10^{-3}= x^2

\rightarrow \sf x = \sqrt{5\ *\ 10^{-3}}

\rightarrow \sf x =0.07071 \ m

3 0
2 years ago
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