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3 years ago

8

Two point charges of equal magnitude are 7.3 cm apart. At the midpoint of the line connecting them, their combined electric fiel

d has a magnitude of 50 N/C .

1 answer:

Delicious77 [7]3 years ago

4 0

Answer:

q₁ = q₂ = Q = 14.8 pC

Explanation:

Given that

q₁ = q₂ = Q = ?

Distance between charges = r =7.3 cm = 0.073 m

Combined electric field = E₁ + E₂ = E = 50 N/C

Using formula

$E=2\frac{kQ}{r^2}$

Rearranging for Q

$Q= \frac{Er^2}{2k}\\\\Q=\frac{(50)(.005329)}{2\times 9\times 10^9}$

$Q=14.8\times 10^{-12}\, C\\\\Q=14.8\, pC$

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You're driving down the highway late one night at 20 m/s when a deer steps onto the road 44 m in front of you. Your reaction tim

never [62]

Answer:

14.0 m

25.1 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Distance traveled in the reaction time

Distance = Speed × Time

$\text{Distance}=20\times 0.5=10\ m$

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-20^2}{2\times -10}\\\Rightarrow s=20\ m$

Distance in which the car will stop is 10+20 = 30.0 m

So, the car will not hit the deer

Distance between the car and deer is 44-30 = 14.0 m

$\text{Distance}=u\times 0.5=0.5u\ m$

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u^2=v^2-2as\\\Rightarrow u^2=0^2-2\times -10\times (44-0.5u)\\\Rightarrow u^2=20(44-0.5u)\\\Rightarrow u^2=880-10u\\\Rightarrow u^2+10u-880=0$

$u=\frac{-10+\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}, u=\frac{-10-\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}\\\Rightarrow u=25.08, -35.08\ m/s$

Maximum speed of the car by which it will not hit the deer is 25.1 m/s

5 0

3 years ago

Read 2 more answers

Calculate the equivalent resistance for both circuits. Series circuit: 2 Ω and 4 Ω Parallel circuit: 2 Ω and 4 Ω Which circuit h

goldenfox [79]

Equivalent resistance is also known as the overall resistance.

For resistors in a series circuit, the total resistance is computed using the formula:

$R_{T} = R_{1}+ R_{2}+ R_{3}... R_{n}$

In other words, you just add up the resistance of each resistor in the series circuit. In your case you only have two resistors. You have 2Ω and 4Ω. So all you need to do is add that up.

$R_{T} = R_{1}+ R_{2}$
$R_{T} = 2 + 4=6$

The total resistance of the series circuit is 6Ω

In a parallel circuit you get the total resistance using the formula:
$\frac{1}{R_{T}} = \frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}...+\frac{1}{R_{n}}$

First you get the sum of all fractions and at the end take the reciprocal of the resulting fraction and divide. So let us take your problem into consideration where you have two resistors that have a resistance of 2Ω and 4Ω.

$\frac{1}{R_{T}} = \frac{1}{R_{1}}+\frac{1}{R_{2}}$
$\frac{1}{R_{T}} = \frac{1}{2}+\frac{1}{4}$
$\frac{1}{R_{T}} = \frac{2}{4}+\frac{1}{4}$
$\frac{1}{R_{T}} = \frac{3}{4}$

Get the reciprocal of the resulting fraction 3/4 and then divide. The reciprocal of 3/4 is 4/3.

4/3 = 1. 33Ω

So if you compare the equivalent resistance of the two circuits, the series circuit has a higher equivalent resistance.

3 0

3 years ago

Read 2 more answers

Describe how you could use two photographs taken at a different time to prove that the moon is in motion

Slav-nsk [51]

<span>You can prove that moon is in motion by taking two photos with the following features:

They are taken at the same hour and minute.
They are taken on two different nights.
They are taken from the same location.

This would allow an accurate comparison and would should the moon's motion.

I hope this helped! :)</span>

5 0

3 years ago

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You are approaching an intersection where you want to make a turn, and you have a green

Nat2105 [25]

Slow down to a safe turning speed before entering the intersection

6 0

2 years ago

A single-wavelength beam of light is pointed at a dark shield with two narrow slits. As a result, an interference pattern forms

lilavasa [31]

Answer:

The slit separation is 2.2μm.

Explanation:

Given that,

Wavelength = 635 nm

Angle = 16.6°

Order number = 1

We need to calculate the slit position

Using formula of slit distance

$d\sin\theta= m\lambda$

$d=\dfrac{m\lambda}{\sin\theta}$

Where, $\lambda$ = wavelength

m = order number

Put the value into the formula

$d=\dfrac{1\times635\times10^{-9}}{\sin 16.6}$

$d=2.2\times10^{-6}\ m$

$d=2.2\ \mu m$

Hence, The slit separation is 2.2μm.

7 0

2 years ago