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UNO [17]
3 years ago
15

How could you demonstrate melting point?

Chemistry
2 answers:
Rus_ich [418]3 years ago
8 0

Melting point, temperature at which the solid and liquid forms of a pure substance can exist in equilibrium. As heat is applied to a solid, its temperature will increase until the melting point is reached. More heat then will convert the solid into a liquid with no temperature change.

EastWind [94]3 years ago
5 0
By seeing how much it is melting
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I really have no idea what to do here sorry. Help please.
horrorfan [7]

1. An ion is a charged atom. A molecule is a neutrally-charged combination of atoms.

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3. An electron dot diagram is a simple way of representing the bond and electronic structure of molecules. A formula is a written representation of the types and numbers of atoms in a molecule.

4. As above...a formula denotes which atoms are in a molecule and how many. For example, H2SO4 tells us there are two hydrogen atoms, one sulfur atom and four oxygen atoms in each molecule of sulfuric acid.

5. An ionic bond is a type of chemical bond that stems from electrostatic attraction between ions with opposite charges. A covalent bond is another type of chemical bond that involves sharing of electrons between atoms in order to achieve a stable electronic structure for the molecule as a whole.

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3 years ago
Comparing Mirrors
mote1985 [20]

Answer:

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convex

concave

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Explanation:

4 0
4 years ago
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Define the dead or void time in HPLC? <br> Plzzz help I’m struggling
marysya [2.9K]

Answer:

2 Answers. The column is filled with the carrier (liquid or gas) before the sample is injected. Thus if there is no interaction between the sample and the column, then the fastest that the sample can get to the detector is the dead time denoted by tM in the diagram.

7 0
3 years ago
Aluminum and oxygen react according to the following equation: 4Al + 3O2 -&gt; 2Al2O3 In a certain experiment, 4.6g Al was react
stiv31 [10]

Answer:

Percent yield: 78.2%

Explanation:

Based on the reaction:

4Al + 3O₂ → 2Al₂O₃

<em>4 moles of Al produce 2 moles of Al₂O₃</em>

<em />

To find percent yield we need to find theoretical yield (Assuming a yield of 100%) and using:

(Actual yield (6.8g) / Theoretical yield) × 100

Moles of 4.6g of Al (Molar mass: 26.98g/mol) are:

4.6g Al × (1mol / 26.98g) = 0.1705 moles of Al.

As 4 moles of Al produce 2 moles of Al₂O₃, theoretical moles of Al₂O₃ obtained from 0.1705 moles of Al are:

0.17505 moles Al × (2 moles Al₂O₃ / 4 moles Al) = <em>0.0852 moles of Al₂O₃</em>,

In grams (Molar mass Al₂O₃ = 101.96g/mol):

0.0852 moles of Al₂O₃ × (101.96g / mol) =

<h3>8.7g of Al₂O₃ can be produced (Theoretical yield)</h3>

Thus, Percent yield is:

(6.8g / 8.7g) × 100 =

<h3>78.2% </h3>
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Answer/Explanation:

Refer to picture below

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