Answer:
a)Change in the speed = 1.41 m/s
b)The final speed will be 3.11 m/s
Explanation:
Given that
Acceleration ,a= 4.7 x 10⁻³ m/s²
a)
We know that
v= u + a t
v=final speed ,u=initial speed
t= time ,a= acceleration
Change in the speed
v- u = a t
t= 5 min = 5 x 60 s = 300 s
v- u = 4.7 x 10⁻³ x 5 x 60 m/s
v-u = 1.41 m/s
Change in the speed = 1.41 m/s
b)
Given that
u= 1.7 m/s
v-u = 1.41 m/s
v= 1.7 + 1.41 m/s
v=3.11 m/s
The final speed will be 3.11 m/s
Answer:
3. velocity is zero.
Explanation:
The velocity of a simple harmonic motion is given by

Here, <em>ω</em> is the angular velocity, <em>A</em> is the amplitude (or maximum displacement from the equilibrium point) and <em>x</em> is the displacement at any time.
At maximum displacement, <em>x </em>=<em> A</em>.<em> </em>Then

Therefore, at maximum displacement, velocity is 0.
Practically, this can be observed in a simple pendulum. As it approaches the maximum displacement, its velocity reduces. It becomes zero at this point and then reverses as the pendulum changes course. Then the velocity begins to increase. It becomes maximum at the equilibrium point but once past that, the velocity begins to reduce as it approaches the other amplitude.
For acceleration,

It follows that at maximum displacement, the acceleration is a maximum. The negative sign indicates that it is in an opposite direction to the displacement. Both kinetic energy (
) and linear momentum (
) are proportional to velocity; they are therefore both zero at the maximum displacement.
Answer:
solved
Explanation:
a) F_net = (F2 - F3)i - F1 j
b) |Fnet| = sqrt( (F2 - F3)^2 + F1^2)
= sqrt( (9- 5)^2 + 1^2)
= 4.123 N
c) θ = tan^-1( (Fnet_y/Fnet_x)
= tan^-1( -1/(9-5) )
= -14.036°
Answer:652.05 J
Explanation:
Given
Weight of lifter 
vertical distance move 
Work done in lifting the weight is equal change in Potential Energy of weight
Change in Potential Energy 

therefore work done is equal to
I believe it is true . Somebody correct me if I’m wrong!