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Mkey [24]
3 years ago
8

What is the wavelength of a light with a frequency of 6.98x10to the 14th power

Physics
1 answer:
NeX [460]3 years ago
5 0
It is callled do it your self  you you you
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A. 2kg<br><br> B. 6kg<br><br> C. 8kg<br><br> D. 14kg
Sati [7]

Answer:

A

Explanation:

We know the force is (16N-12), which is 4N, and we know the acceleration is 2 m/s^2. Meaning, we can solve the formula m = F / a (mass equals force divided by acceleration), and we get 2kg.

7 0
3 years ago
Which two questions can be used to identify criteria for how successful the design of an efficient high altitude drone is?
AfilCa [17]

Answer:

Explanation:

Remark

Though you  do not know what height the previous drone reached, I would think reading 8000 m would be quite an accomplishment. Answer 1: A

B: I wouldn't pick B. Increased cost isn't going to contribute to design success.

C. If the efficiency is low to start with, increasing it some won't matter. On the other hand if the efficiency is moderate or good increasing it by 35% is a good thing. Let's hold on to this answer.

D: It has to work at low altitudes in order to work at high altitudes. I wouldn't pick D

E: Popularity is something you never know will happen. I think C is your best second answer.

Answer: A and C

7 0
2 years ago
PLEASE HELP ASAP!!!!!! <br> What should each experiment only have one of? <br> variable or constant
slega [8]

Answer:

the answer should be a constant

hope this helps!!

3 0
4 years ago
Read 2 more answers
In a double-slit experiment, it is observed that the distance between adjacent maxima on a remote screen is 1.0 cm. What happens
kobusy [5.1K]

Answer:

C) It increases to 2.0 cm

Explanation:

In a double-slit diffraction experiment, the distance on the screen between two adjacent maxima is given by

\Delta y = \frac{\lambda D}{d}

where

\lambda is the wavelength of the wave

D is the distance of the screen from the slits

d is the separation between the slits

In this problem, the initial distance between adjacent maxima is 1.0 cm. Later, the slit separation is cut in a half, which means that the new slit separation is

d'=\frac{d}{2}

Substituting into the equation, we find that the new separation between the maxima is

\Delta y' = \frac{\lambda D}{d/2}=2(\frac{\lambda D}{d})=2\Delta y

So, the distance increases by a factor 2: therefore, the new separation between the maxima will be 2.0 cm.

5 0
3 years ago
a rocket burns propellant at a rate of dm/dt = 3.0 kg/s, ejecting gases with a speed of 8000 m/s relative to the rocket. Find th
elena-s [515]

Answer: 24 kN

Explanation:

Given

The rocket burns propellant at the rate of

\dfrac{dm}{dt}=3\ kg/s

Relative ejection of gases v=8000\ m/s

The magnitude of thrust force is given by

F_t=v\dfrac{dm}{dt}\\\\F_t=8000\times 3=24,000\ N\ or\ 24\ kN

5 0
3 years ago
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