Given :
A compound has a molar mass of 129 g/mol .
Empirical formula of compound is C₂H₅N .
To Find :
The molecular formula of the compound.
Solution :
Empirical mass of compound :
Now, n-factor is :
Multiplying each atom in the formula by 3 , we get :
Molecular Formula, C₆H₁₅N₃
Answer:
0.0400M of KI
Explanation:
Molarity is an unit of concentration defined as the ratio between moles of solute and liters of solution.
When you add 10.0 mL of 0.10M KI and 15.0mL, total volume is:
25.0mL = <em>0.025L of solution</em>
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And moles of KI are:
0.0100L × 0.10M = <em>0.00100 moles of KI</em>
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Thus, molarity is:
0.00100 moles / 0.025L = <em>0.0400M of KI</em>
Answer:
C.
Explanation:
If the students want to know at what percent of CO2 in the air the plant will grow at the fastest, then the percent of CO2 should be a different value for each plant in the table.
There are 2 tables that have different values for the CO2 - the tables in answer choices C and D.
Since the students only want to know how the amount of CO2 affects the plant, every other variable should remain constant.
The only answer choice that has a changing value for the percent of CO2 and a constant value for every other variable is C.
Answer:
Over hundreds of years
Explanation:
Just did the test and got it right
