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2 years ago

NEED HELP!! PHYSICS PROBLEM

Physics

1 answer:

garik1379 [7]2 years ago

7 0

Answer:

Explanation:

At Y, horizontal force is greater than downward force so E or L. However L seems to be more appropriate since horizontal force in L is less than E

At Z, horizontal force is less than downward force so D

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A 0.50 kg toy is attached to the end of a 1.0 m very light string. The toy is whirled in a horizontal circular path on a frictio

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Answer:

The maximum speed will be 26.475 m/sec

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We have given mass of the toy m = 0.50 kg

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For without breaking the string tension must be equal to the centripetal force

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3 years ago

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Answer:

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Answer:

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∆T = Mv^2(Y - 1)/2R k

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