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ch4aika [34]
3 years ago
7

An HCl solution has a pH of 3.350. After some NaOH was

Chemistry
1 answer:
Romashka [77]3 years ago
8 0

Answer:

4.47x10^-4M

Explanation:

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Explanation:

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VA 19.75-g sample was heated by 12.35 calories. The specific heat of the sample is 0.125 cal/g°C. What was the initial temperatu
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Answer:

31.9 °C  

Explanation:

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m = 19.75 g

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Calculations

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ΔT  = 12.35/(2.406 °C⁻¹) = 5.13 °C

(b) Calculate T₂

ΔT = T₂ - T₁

T₁ = T₂ - ΔT = 37.0 °C - 5.13 °C = 31.9 °C

The original temperature was 31.9 °C.

 

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L
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