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4 years ago

9

Two trains traveling on parallel tracks are going toward each other from a distance of 552 miles. If the freight train is moving

at 38 mph and the passenger train is moving at 54 mph, when will the trains pass each other?

1 answer:

irga5000 [103]4 years ago

3 0

Answer:

6hrs

Explanation:

t = time taken until the trains pass by each other/hrs

38 + 54 = 92

Use time = distance/speed:

t = 552/92 = 6

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Answer:

The answer is below

Explanation:

Using Coulomb's law of electric field which is:

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3 years ago

The two structural members, one of which is in tension and the other in compression, exert the indicated forces on joint o. dete

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We're going to remedy it with the parallelogram law.
$\alpha$ = one hundred eighty - 30 - 70 = eighty degrees
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4 years ago

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4 years ago

Read 2 more answers

. Egbert is in a rowboat four miles from the nearest point on Egbert a straight shoreline. He wishes to reach a house 12 miles f

swat32

Answer:

$t=\frac{13}{3} =4.33\ mi.hr^{-1}$

Explanation:

Given:

Distance from the shore, $s=4\ mi$

distance of house from the shore, $h=12\ mi$

speed of rowing, $v_r=3\ mi.hr^{-1}$

speed of walking, $v_w=4\ mi.hr^{-1}$

<em>For the least amount of time to reach the house one must row at the nearest point on the shore and then walk from there.</em>

<u>Now the time taken to reach the shore:</u>

$t_s=\frac{s}{v_s}$

$t_s=\frac{4}{3}\ mi.hr^{-1}$

<u>Time taken in walking to house from the shore:</u>

$t_h=\frac{h}{v_w}$

$t_h=\frac{12}{4}$

$t_h=\frac{12}{4}$

$t_h=3\ mi.hr^{-1}$

<u>Therefore total time taken:</u>

$t=t_h+t_s$

$t=\frac{13}{3} =4.33\ mi.hr^{-1}$

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3 years ago

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