Electromagnetic waves are _______

If a race car wants to change its velocity then a net force is required to cause the necessary

pashok25 [27]

Answer:acceleration

Explanation:

8 0

4 years ago

The formula d = 1.1 t 2 + t + 1 expresses a car's distance (in feet to the north of an intersection, d , in terms of the number

Phantasy [73]

d(t) = 1.1t² + t + 1

The constant speed required to cover the same distance between t = 3 to t = 5 is the same as the average speed over that same time interval. It is given by:

v = Δx/Δt

v = average speed, Δx = change in distance, Δt = elapsed time

Given values:

Δx = d(5) - d(3) = 19.6ft

Δt = 5s - 3s = 2s

Plug in and solve for v:

v = 19.6/2

v = 9.8ft/s

5 0

4 years ago

Read 2 more answers

A ball is thrown vertically upward from the top of a building 112 feet tall with an initial velocity of 96 feet per second. The

nordsb [41]

Answer:

$t=6.96s$

Explanation:

From this exercise, our knowable variables are hight and initial velocity

$v_{oy}=96ft/s$

$y_{o}=112ft$

To find how much time does the ball strike the ground, we need to know that the final position of the ball is y=0ft

$y=y_{o}+v_{oy}t+\frac{1}{2}gt^{2}$

$0=112ft+(96ft/s)t-\frac{1}{2}(32.2ft/s^{2})t^{2}$

Solving for t using quadratic formula

$t=\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

$a=-\frac{1}{2} (32.2)\\b=96\\c=112$

$t=-0.999s$ or $t=6.96s$

Since time can't be negative the answer is t=6.96s

7 0

3 years ago

helpppp I just saw my crush when I was walking out of a supermarket and like I was looking a mess so now I'm just wondering how

UkoKoshka [18]

Answer:

okay

Explanation:

(wish i could help but im just answering for points)

3 0

3 years ago

g When a thin-filament light bulb is connected to two 1.6 V batteries in series, the current is 0.075 A. What is the resistance

larisa [96]

Answer:

R = 42.67 ohms

Explanation:

It is given that, a thin-filament light bulb is connected to two 1.6 V batteries in series, the current is 0.075 A.

It means that when two batteries are connected in series, then the total voltage is 3.2 volts

Let R is the resistance of the glowing thin-filament bulb. So, using Ohm's law we get :

$V=IR\\\\R=\dfrac{V}{I}$

So,

$R=\dfrac{3.2}{0.075}\\\\R=42.67\ \Omega$

So, the resistance of the bulb is 42.67 ohms.

5 0

3 years ago

Electromagnetic waves are ________ waves.